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weqwewe [10]
3 years ago
8

HELPPP PLSSSS ITS ALMOST DUE IN 1 HOUR WILL GIVE BRAINLIEST THANKS AND 5 STARSSS

Mathematics
2 answers:
Inessa05 [86]3 years ago
6 0
H=($13-$2.50)/3

hope it helps
saul85 [17]3 years ago
3 0

Answer:

3.5

Step-by-step explanation:

13-2.50= 10.5

10.5/3 is 3.5

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How many times does the graph of 4x = 32 - x2 cross the x-axis ?
Molodets [167]

Answer:

x=4 orx=- 8

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

4

x

=

−

x

2

+

32

Step 2: Subtract -x^2+32 from both sides.

4

x

−

(

−

x

2

+

32

)

=

−

x

2

+

32

−

(

−

x

2

+

32

)

x

2

+

4

x

−

32

=

0

Step 3: Factor left side of equation.

(

x

−

4

)

(

x

+

8

)

=

0

Step 4: Set factors equal to 0.

x

−

4

=

0

or

x

+

8

=

0

x

=

4

or

x

=

−

8

5 0
3 years ago
Read 2 more answers
5X/2 = 20<br> WHAT IS THE ANSWER TO X
mariarad [96]

Answer:

The answer is 8

Step-by-step explanation:

29 X 2 is 40

40 divided by 5 is 8

4 0
3 years ago
You just bought a dog, so you want to install a fence around your yard. The yard is rectangular and is 35.8 feet wide by 55.2 fe
Assoli18 [71]
$7,904 is the answer simple math
4 0
3 years ago
What is the slope of the line tangent to the curve y+2 = (x^2/2) - 2siny at the point (2,0)?
kirza4 [7]
<span>, y+2 = (x^2/2) - 2sin(y) so we are taking the derivative y in respect to x so we have dy/dx use chain rule on y so y' = 2x/2 - 2cos(y)*y'

</span><span>Now rearrange it to solve for y' y' = 2x/2 - 2cos(y)*y' 0 = x - 2cos(y)y' - y' - x = 2cos(y)y' - y' -x = y'(2cos(y) - 1) -x/(2cos(y) - 1) = y'
</span><span>we know when f(2) = 0 so thus y = 0 so when f'(2) = -2/(2cos(0)-1)
</span><span>2/2 = 1
</span><span>f'(2) = -2/(2cos(0)-1) cos(0) = 1 thus f'(2) = -2/(2(1)-1) = -2/-1 = 2 f'(2) = 2
</span>
6 0
3 years ago
Read 2 more answers
W - 6= -4w - 11<br><br> I don’t get it
jolli1 [7]

Answer:

Well if your solving for "W" it will be "W= -4w - 5"

Hope it helps :)

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
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