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3 years ago

HELPPP PLSSSS ITS ALMOST DUE IN 1 HOUR WILL GIVE BRAINLIEST THANKS AND 5 STARSSS

Mathematics

2 answers:

Inessa05 [86]3 years ago

6 0

H=($13-$2.50)/3

hope it helps

saul85 [17]3 years ago

3 0

Answer:

3.5

Step-by-step explanation:

13-2.50= 10.5

10.5/3 is 3.5

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A barn has 11 heads and 36 legs. How many are chicks and how many are pigs

Helen [10]

answer is 7 pigs and 4 chicks

pigs' legs = 7 x 4 = 28

chicks' legs = 4 x 2 = 8

28 + 8 = 36 legs

7 0

3 years ago

Read 2 more answers

Using the following equation, find the center and radius: x2 −2x + y2 − 6y = 26 (5 points)

Lisa [10]

Answer:

Center: (1,3)

Radius: 6

Step-by-step explanation:

Hi there!

$x^2-2x + y^2 - 6y = 26$

Typically, the equation of a circle would be in the form $(x-h)^2+(y-k)^2=r^2$ where $(h,k)$ is the center and $r$ is the radius.

To get the given equation $x^2-2x + y^2 - 6y = 26$ into this form, we must complete the square for both x and y.

<u>1) Complete the square for x</u>

Let's take a look at this part of the equation:

$x^2-2x$

To complete the square, we must add to the expression the square of half of 2. That would be 1² = 1:

$x^2-2x+1$

Great! Now, let's add this to our original equation:

$x^2-2x+1+y^2-6y = 26$

We cannot randomly add a 1 to just one side, so we must do the same to the right side of the equation:

$x^2-2x+1+y^2-6y = 26+1\\x^2-2x+1+y^2-6y = 27$

Complete the square:

$(x-1)^2+y^2-6y = 27$

<u>2) Complete the square for y</u>

Let's take a look at this part of the equation $(x-1)^2+y^2-6y = 27$ :

$y^2-6y$

To complete the square, we must add to the expression the square of half of 6. That would be 3² = 9:

$y^2-6y+9$

Great! Now, back to our original equation:

$(x-1)^2+y^2-6y+9= 27$

Remember to add 9 on the other side as well:

$(x-1)^2+y^2-6y+9= 27+9\\(x-1)^2+y^2-6y+9= 36$

Complete the square:

$(x-1)^2+(y-3)^2= 36$

<u>3) Determine the center and the radius</u>

$(x-1)^2+(y-3)^2= 36$

$(x-h)^2+(y-k)^2=r^2$

Now, we can see that (1,3) is in the place of (h,k). 36 is also in the place of r², making 6 the radius.

I hope this helps!

3 0

3 years ago

Read 2 more answers

Find the dimensions of a rectangle with area 512 m2 whose perimeter is as small as possible. (If both values are the same number

Masja [62]

Answer:

Step-by-step explanation:

Length the length and breadth of the rectangle be x and y.

Area of the rectangle A = Length * breadth

Perimeter P = 2(Length + Breadth)

A = xy and P = 2(x+y)

If the area of the rectangle is 512m², then 512 = xy

x = 512/y

Substituting x = 512/y into the formula for calculating the perimeter;

P = 2(512/y + y)

P = 1024/y + 2y

To get the value of y, we will set dP/dy to zero and solve.

dP/dy = -1024y⁻² + 2

-1024y⁻² + 2 = 0

-1024y⁻² = -2

512y⁻² = 1

y⁻² = 1/512

1/y² = 1/512

y² = 512

y = √512 m

On testing for minimum, we must know that the perimeter is at the minimum when y = √512

From xy = 512

x(√512) = 512

x = 512/√512

On rationalizing, x = 512/√512 * √512 /√512

x = 512√512 /512

x = √512 m

Hence, the dimensions of a rectangle is √512 m by √512 m

5 0

4 years ago

The graphs of f(x)=2x+4 and g(x)=10−4x intersect at (1, 6) . What is the solution of the equation 2x+4=10−4x ? Enter you

Yuliya22 [10]

Answer:

$x=1$

Step-by-step explanation:

we have

$f(x)=2x+4$ -----> equation A

$g(x)=10-4x$ ----> equation B

we know that

The solution of the system of equations is the point $(1,6)$

The solution of the equation $2x+4=10-4x$ is equal to the x-coordinate of the solution of the system of equations

therefore

The solution is $x=1$

7 0

3 years ago

In ΔBCD, the measure of ∠D=90°, BD = 13, DC = 84, and CB = 85. What is the value of the cosine of ∠C to the nearest hundredth?

Morgarella [4.7K]

Answer: 0.99

Step-by-step explanation: sin 90 Divided by 85 = sin x divided by 13

sin x =13x sin 90 divided by 85

sin x = 13divided by 85

sin x = .152941176

arc sine of .152941176= 8.79741071 degrees

cos 8.79741071 = .988235294

.99

8 0

3 years ago