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Vilka [71]
3 years ago
14

* ae. This number in unit form is all mixed up! Convert it to standard form. 4 hundred thousands 16 thousands 4 hundreds 21 tens

12 ones​
Mathematics
1 answer:
DiKsa [7]3 years ago
7 0

Answer: 416, 622

Step-by-step explanation:

First, let's look at the hundred thousands place.

We have 4 hundred thousand, which can be rewritten as 400,000.

Then, we have our ten thousand place in which we have sixteen thousand, which can be rewritten as 16,000.

Next, we have our hundreds place. Here, we have four-hundred, or 400.

After that, we have 21 tens, which can be rewritten as 210.

Lastly, we have 12 ones.

Now, if we add all of these together, we get:

400,000 + 16,000 + 400 + 210 + 12 = <em>416,622</em>

(Hope this helps!)

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The perimeter of a triangular field is 120m. Two of the sides are 21m and 40m.Calculate the largest angle of the field.
Mama L [17]

Answer:

the largest angle of the field is 149⁰

Step-by-step explanation:

Given;

perimeter of the triangular filed, P = 120 m

length of two known sides, a and b = 21 m and 40 m respectively

The length of the third side is calculated as follows;

a + b + c = P

21 m  + 40 m  + c = 120 m

61 m +  c = 120 m

c = 120 m - 61 m

c = 59 m

                         B

                     ↓            ↓  

                  ↓                          ↓

                ↓                                       ↓

            A →  →  → →  →  → →  → →    →    →  C

Consider ABC as the triangular field;

Angle A is calculated by applying cosine rule;

a^2 = b^2 + c^2 - 2bc \ Cos A\\\\Cos \ A = \frac{b^2 + c^2 - a^2}{2bc} \\\\Cos \ A = \frac{40^2 + 59^2 - 21^2}{2 \times 40 \times 59} \\\\Cos \ A = 0.983\\\\A = Cos ^{-1} (0.983)\\\\A = 10.6 \ ^0

Angle B is calculated as follows;

Cos \ B = \frac{a^2 + c^2 - b^2}{2ac} \\\\Cos \ B = \frac{21^2 + 59^2 - 40^2}{2 \times 21 \times 59} \\\\Cos \ B = 0.937\\\\B= Cos ^{-1} (0.937)\\\\B = 20.5 \ ^0

Angle C is calculated as follows;

Cos \ C = \frac{a^2 + b^2 - c^2}{2ab} \\\\Cos \ C = \frac{21^2 + 40^2 - 59^2}{2 \times 21 \times 40} \\\\Cos \ C = -0.857\\\\C = Cos ^{-1} (-0.857)\\\\C = 149\ ^0

Therefore, the largest angle of the field is 149⁰.

       

8 0
3 years ago
Help I’m not sure if this is correct number 4
Katena32 [7]

Answer:

-12= -12

Step-by-step explanation:

You're correct dw!

3 0
1 year ago
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