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Alex
3 years ago
6

I really struggling the question can you help me ​

Chemistry
1 answer:
Dmitrij [34]3 years ago
6 0
You need to find number of moles of methane and oxygen. then make ratios

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D. potassium + iodine →
aliina [53]

Answer:

The missing reagents are.

Potassium + Iodine =<u> Potassium iodide</u>

<u>Calcium</u> + oxygen = Calcium oxide

Beryllium +<u> Bromine</u> = Beryllium bromide

<u>Copper + Oxygen</u> = Copper oxide

Explanation:

The balanced equation can be written as:

1.Potassium + Iodine =<u> Potassium iodide</u>

2K(s)+I_{2}(s)\rightarrow 2KI(s)

Here K = potassium

I2 = Iodine

KI = potasssium iodide.

2.<u>Calcium</u> + oxygen = Calcium oxide

2Ca(s)+O_{2}(g)\rightarrow 2CaO(s)

Ca = calcium

O2 = oxygen

CaO = Calcium Oxide

3.Beryllium +<u> Bromine</u> = Beryllium bromide

Be(s)+Br_{2}(g)\rightarrow BeBr_{2}(s)

Here,

Be = beryllium

Br2 = bromine

BeBr2 = Beryllium Bromide

4. Copper + Oxygen = Copper oxide

2Cu(s)+O_{2}(g)\rightarrow 2CuO(s)

Cu = Copper

O2 = oxygen

CuO = Copper Oxide

5 0
3 years ago
Why do non-metal aroms form covalent bonds e.g. H2O​
Oksana_A [137]

Answer:

Covalent bonds usually occur between nonmetals. For example, in water (H2O) each hydrogen (H) and oxygen (O) share a pair of electrons to make a molecule of two hydrogen atoms single bonded to a single oxygen atom. ... Covalent compounds tend to be soft, and have relatively low melting and boiling points.

7 0
3 years ago
What is the volume of an object with a mass of 31g and density of 444g/ml​
Tanzania [10]

Answer:

<h2>The answer is 0.07 mL</h2>

Explanation:

The volume of a substance when given the density and mass can be found by using the formula

volume =  \frac{mass}{density} \\

From the question

mass = 31 g

density = 444 g/mL

We have

volume =  \frac{31}{444}   \\  = 0.06981...

We have the final answer as

<h3>0.07 mL</h3>

Hope this helps you

5 0
3 years ago
If 45.0 mL of ethanol (density =0.789g/mol) initially at 6.0°C mix with 45.0 mL of water (density =1.0 g/mol) initially at 28.0°
Likurg_2 [28]

The final temperature of the mixture : 21.1° C  

<h3>Further explanation  </h3>

The law of conservation of energy can be applied to heat changes, i.e. the heat received / absorbed is the same as the heat released  

Q in(gained) = Q out(lost)  

Heat can be calculated using the formula:  

Q = mc∆T  

Q = heat, J  

m = mass, g  

c = specific heat, joules / g ° C  

∆T = temperature difference, ° C / K  

Q ethanol=Q water

mass ethanol=

\tt mass=\rho\times V\\\\mass=0.789\times 45=35.505~g

mass water =

\tt mass=1~g/ml\times 45~ml=45~g

then the heat transfer :

\tt 35.505\times 2.42~J/g^oC\times (t-6)=45\times 4.18~J/g^oC\times (28-t)\\\\85.922t-515.533=5266.8-188.1t\\\\274.022t=5782.33\rightarrow t=21.1^oC

5 0
3 years ago
A certain ore is 37.3% nickel by mass how many kilograms of this ore would you need to dig up to have 10.0g of nickel
jeka57 [31]
If the grade of the ore is 37.3% nickel, then the unknown quantity to get 10 grams of nickel is 0.373 x = 10 grams or x = 10/0.373=26.8 grams or 0.0268 kg needed to dig up to recover the 10 grams of nickel. At this grade of ore, 1 kilogram would yield 373 grams of nickel. 
7 0
3 years ago
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