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Marina CMI [18]
2 years ago
9

When an electron is removed the atoms charge changes to a what?

Chemistry
1 answer:
inna [77]2 years ago
6 0

Answer:

It make the atom octet from i.e more stable form.

Explanation:

A neutral sodium atom is likely to achieve an octet in its outermost shell by losing its one valence electron. Na -----> Na+ e-

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A. monotomic ionic
ASHA 777 [7]

Answer:

Binary compound

Explanation:

Binary compounds:

The compounds which are made up of the atoms of only two elements are called binary compounds.

For example:

The following compounds are binary:

HCl

H₂O

NH₃

HCl is binary because it is composed of only hydrogen and chlorine. Ammonia is also binary compound because it is made up of only two elements nitrogen and hydrogen.

water is also binary because it is also made up of only two elements hydrogen and oxygen.

SF₆ is binary compound because it consist of atoms of only two elements i.e, sulfur and fluorine.

7 0
3 years ago
The properties of a mineral depend on the ________ of mineral being examined.
professor190 [17]

The properties of a mineral depend on the kind of atoms of mineral being examined

3 0
3 years ago
Does adding 1 mol of NaCl to 1 kg of water lower the vapor pressure of water to the same extent, a lesser extent, or a greater e
igor_vitrenko [27]

Answer:

Adding 1 mol of NaCl to 1 kg of water lower the vapor pressure of water <em><u>to the same extent</u></em>  by adding 1 mol of C_06H_{12}O_6 to 1 kg of water.

Explanation:

1) Moles of NaCl ,n_1=1 mol

Mass of water = m= 1 kg = 1000 g

Moles of water = n_2=\frac{1000 g}{18 g/mol}=55.55 mol

Vapor pressure of the solution = p

Vapor pressure of the pure solvent that is water = p_o=17.5 Torr

Mole fraction of solute(NaCl)= \chi_1=\frac{n_1}{n_1+n_2}

\frac{p_o-p}{p_o}=\frac{n_1}{n_1+n_2}

\frac{17.5 Torr-p}{17.5 Torr}=\frac{1 mol}{1 mol+55.55 mol}

p=17.19 Torr

The vapor pressure for the NaCl solution at 17.19 Torr.

2) Moles of sucrose ,n_1=1mol

Mass of water = m  = 1 kg = 1000 g

Moles of water = n_2=\frac{1000 g}{18 g/mol}=55.55 mol

Vapor pressure of the solution = p'

Vapor pressure of the pure solvent that is water = p_o=17.5 Torr

Mole fraction of solute ( glucose)= \chi_1=\frac{n_1}{n_1+n_2}

\frac{p_o-p}{p_o}=\frac{n_1}{n_1+n_2}

\frac{17.5 Torr-p}{17.5 Torr}=\frac{1 mol}{1 mol+55.55 mol}

p'=17.19 Torr

The vapor pressure for the glucose solution at 17.19 Torr.

p = p' = 17.19 Torr

Adding 1 mol of NaCl to 1 kg of water lower the vapor pressure of water to the same extent  by adding 1 mol of C_06H_{12}O_6 to 1 kg of water.

3 0
3 years ago
The measurement 1.00540 g contains<br> significant figures. *<br> 10<br> 3<br> 4<br> 5<br> O<br> 6
antiseptic1488 [7]
It contains 6 sig figs
4 0
3 years ago
How is the periodic table arranged ( give two ways)
vlabodo [156]
Left side metals right side non metals. arrganged in groups (columns) and periods (rows), each group tells you amount of valence electrons
7 0
2 years ago
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