1 year ago

Need help with this worksheet

1 answer:

3 0

So you have to draw a line throw the papa per

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lesya692 [45]

V1/T1 = V2/T2

Substitute the value use ratio and proportion. Use calculator.

V1 = (V2 x T1) / T2

1 is initial, 2 is final

4 0

2 years ago

OverLord2011 [107]

In a bag of peas that weighs 454 grams, there are between 1261 and 4540 peas.

The average pea weighs between 0.1 and 0.36 grams.

If we take the lower value (0.1 g/pea), the number of peas in 454 g is:

$454 g \times \frac{1pea}{0.1 g} = 4540pea$

If we take the higher value (0.36 g/pea), the number of peas in 454 g is:

$454 g \times \frac{1pea}{0.36 g} \approx 1261pea$

In a bag of peas that weighs 454 grams, there are between 1261 and 4540 peas.

You can learn more about conversion factors here: brainly.com/question/1844638

6 0

2 years ago

yarga [219]

Answer:

the mass number is the number of protons and neutrons added and the average atomic mass is the weight of the protons and neutrons

4 0

3 years ago

hodyreva [135]

Germanium is classified as a metalloid.

6 0

2 years ago

Zanzabum

Answer:

I think that you want no, of moles

Explanation:

no, of mole of this amount= 15/44 = 0.341 mole

8 0

3 years ago