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Bess [88]
3 years ago
12

Are iron filings a pure substance?

Chemistry
1 answer:
Elena L [17]3 years ago
8 0
Yes they are a pure substance 
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I really need help ! This is science
lina2011 [118]

Answer:

7. genetics because hereditary is not the study of hereditary.

8. is hereditary because it is the study of how things pass on to next generation what is inherited.

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Lakes can disappear due to?
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Lakes can vanish due to natural processes and human activity. Bacteria break down lake species' bodies and release nutrients into the water when they die. Eutrophication is the accumulation of nutrients in a lake over time. Lakes and rivers all throughout the world have dried up as a result of rising water demand and a warmer environment. Overpumping of aquifers and excessive diversion of water from rivers.

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6 0
2 years ago
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6 Li + Zn3(PO4)2 ------- > 2 Li3PO4 + 3 Zn
bogdanovich [222]

Moles of Lithium phosphate : 0.495

<h3>Further explanation</h3>

Given

6 Li + Zn₃(PO₄)₂ ------- > 2 Li₃PO₄ + 3 Zn

Required

Moles of Lithium phosphate

Solution

moles of Zinc(Ar=65,38 g/mol) :

= mass : Ar

= 48.6 : 65.38

= 0.743

From equation, mol ratio of Zn :  Li₃PO₄ = 3 : 2, so mol  Li₃PO₄ :

= 2/3 x mol Zn

= 2/3 x 0.743

= 0.495

3 0
3 years ago
On the pH scale, where can you find strong acids and strong bases?
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6 0
3 years ago
What is the heat of reaction (ΔH°rxn) for the combustion of acetone (C3H6O) given the following thermochemical equations? 1. 3 C
nydimaria [60]

Answer : The enthalpy of combustion of C_3H_6O will be -1775 kJ

Explanation :

According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.

According to this law, the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.

The combustion of C_3H_6O will be,

C_3H_6O(l)+4O_2(g)\rightarrow 3CO_2(g)+3H_2O(l)    \Delta H_{comb}=?

The intermediate balanced chemical reaction will be,

(1) 3C(s)+3H_2(g)+\frac{1}{2}O_2(g)\rightarrow C_3H_6O(l)     \Delta H_1=-285.0kJ

(2) C(s)+O_2(g)\rightarrow CO_2(g)    \Delta H_2=-394.0kJ

(3) H_2(g)+\frac{1}{2}O_2(g)\rightarrow H_2O(l)    \Delta H_3=-286.0kJ

Now we are reversing the reaction 1, multiplying reaction 2 and 3 by 3 and then adding all the equations, we get :

(1) C_3H_6O(l)\rightarrow 3C(s)+3H_2(g)+\frac{1}{2}O_2(g)     \Delta H_1=285.0kJ

(2) 3C(s)+3O_2(g)\rightarrow 3CO_2(g)    \Delta H_2=3\times -394.0kJ=-1182.0kJ

(3) 3H_2(g)+\frac{3}{2}O_2(g)\rightarrow 3H_2O(l)    \Delta H_3=3\times -286.0kJ=-858.0kJ

The expression for enthalpy of combustion of C_3H_6O will be,

\Delta H_{comb}=\Delta H_1+\Delta H_2+\Delta H_3+\Delta H_4

\Delta H_{comb}=(285.0)+(-1182.0)+(-858.0)

\Delta H_{comb}=-1755kJ

Therefore, the enthalpy of combustion of C_3H_6O will be -1775 kJ

3 0
4 years ago
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