C = 12.818 mg CO2 (1 mmol CO2/44 mg CO2) (1 mmol C/1 mmol
CO2) = 0.29 mmol
H = 3.675 mg of H2O (1 mmol H2O/18 mg H2O) (2 mmol H/1
mmol H2O) = 0.41 mmol
N = (4.725 mg – 0.29 * 12 – 0.41 * 1) * (1 mmol/14 mg) =
0.06 mmol
Divide everything by the smallest number:
C = 0.29/0.06 = 4.8 ~ 5
<span>H = 0.41/0.06 = 6.8 ~
7</span>
N = 0.06/0.06 = 1
Empirical formula is:
<span>C5H7N</span>
Answer:
1.45 x 10⁻² g CO₂
Explanation:
To find the mass of carbon dioxide, you need to (1) convert grams CH₄ to moles CH₄ (via molar mass), then (2) convert moles CH₄ to moles CO₂ (via mole-to-mole ratio from reaction coefficients), and then (3) convert moles CO₂ to grams CO₂ (via molar mass). The final answer should have 3 sig figs to reflect the given value (5.30 x 10⁻³ g).
Molar Mass (CH₄): 12.011 g/mol + 4(1.008 g/mol)
Molar Mass (CH₄): 16.043 g/mol
Combustion of Methane:
1 CH₄ + 2 O₂ ---> 2 H₂O + 1 CO₂
Molar Mass (CO₂): 12.011 g/mol + 2(15.998 g/mol)
Molar Mass (CO₂): 44.007 g/mol
5.30 x 10⁻³ g CH₄ 1 mole 1 mole CO₂ 44.007 g
--------------------------- x ---------------- x --------------------- x ----------------- =
16.043 g 1 mole CH₄ 1 mole
= 0.0145 g CO₂
= 1.45 x 10⁻² g CO₂
Answer:
Aluminium oxide has higher melting point than aluminium chloride because there nay be some impurities in the oxide which affects the intermolecular force of attraction
Answer:
• long time lag between planning and operation.
• cost.
• weapons proliferation risk.
• meltdown risk.
• mining lung cancer risk.
• carbon-equivalent emissions and air pollution.
• waste risk.
Explanation:
hope this help <33
Candela is the correct answer. In measuring the brightness or luminosity of the bulb and you want to use the metric system, candela is the unit to be used. You are correct that candela is the unit of light intensity. The term candela is the Latin for candle which signifies light.<span> </span>
