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LenaWriter [7]
3 years ago
10

How many grams of water are required to produce 5.50L of hydrogen gas at 25.0 degrees C and 755mmHg?

Chemistry
1 answer:
stiv31 [10]3 years ago
3 0

Answer is: 4.02 grams of water are required.
Chemical reaction: BaH₂ + 2H₂O → Ba(OH)₂ + 2H₂.
Ideal gas law: p·V = n·R·T.
p = 755 mm Hg ÷ 760.0 mmHg / atm = 0.993 atm.
T = 25 + 273.15 = 298.15 K.
V(H₂) = 5.50 L.
R = 0,08206 L·atm/mol·K.
n(H₂) = 0.993 atm · 5.5 L ÷ 0,08206 L·atm/mol·K · 298.15 K.
n(H₂) = 0.223 mol.
From chemical reaction: n(H₂O) : n(H₂) = 1 : 1.
n(H₂O) = 0.223 mol.
m(H₂O) = 0.223 mol · 18 g/mol.
m(H₂O) = 4.02 g.
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Answer:

The Photosynthesis process

Explanation:

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The general equation of photosynthesis is:

6 CO_{2}                 + 6 H_{2} O + Energy  -> C_{6} H_{12} 12O_{6}  +  6 O_{2}

6 CO2                + 6 H2O + Energy  -> C6H12O6         +  6 O2  

Carbon Dioxide  + water  +  Light   -> Glucose (sugar) + Oxygen

After, this glucose is transformed into pyruvate, and it allowed the release of denosine triphosphate (ATP) by cellular respiration. The ATP is an organic chemical that is requires for the cell to perform any process (any kind or work).

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3 years ago
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True or false. Gas particles never touch each other.
Sati [7]

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False.  In a gas, particles are in continual straight-line motion. The kinetic energy of the molecule is greater than the attractive force between them, thus they are much farther apart and move freely of each other.

Explanation:

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6 0
2 years ago
What was the original pressure in a rigid container if the new pressure is 82.5atm and the temperature was raised from 44C to 67
zhenek [66]

Answer: 54 atm

Explanation:

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3 years ago
the vapor pressure of a naqueous solution is found to be 24.9 mmgh at 25C. what is the mole fraction of solute in this solution?
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Answer:

Mole fraction of solute is 0.0462

Explanation:

To solve this we use the colligative property of lowering vapor pressure.

First of all, we search for vapor pressure of pure water at 25°C  = 23.8 Torr

Now, we convert the Torr to mmHg. Ratio is 1:1, so 23.8 Torr is 23.8 mmHg.

Formula for lowering vapor pressure is:

ΔP = P° . Xm

Where ΔP = P' (Vapor pressure of solution) - P° (Vapor pressure of pure solvent)

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Xm = (24.9 mmHg - 23.8 mmHg) /  23mmHg

Xm = 0.0462

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2 years ago
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