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2 years ago

9

Please help. This is due 1st period

1 answer:

faust18 [17]2 years ago

7 0

Just substitute the value x into the equation y=2x

y = 2x
y = 2(-1)
y = -2

use the same method for the rest

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Write the standard form of the line that passes through the given points. Include your work in your final answer. Type your answ

I am Lyosha [343]

Answer:

|x y 1|

|7 -3 1| = 0

|4 -8 1|

x*(-3*1 - (-8)*1) - y*(7*1 - 4*1) + 1*(7*-8 - 4*-3) = 0

5x - 3y - 44 = 0

Step-by-step explanation:

6 0

1 year ago

when a three-dimensional figure is extended infinitely in all directions, which of the following best describes what is formed?

HACTEHA [7]

Probably A, a plane

I hope this helps you! If it does, please rate as Brainliest :D

7 0

2 years ago

Read 2 more answers

Find three positive numbers whose sum is 140 and whose product is a maximum. (Enter your answers as a comma-separated list.)

Paladinen [302]

Answer:

$\frac{140}{3}, \frac{140}{3}, \frac{140}{3}$

Step-by-step explanation:

Let the numbers be $x, y\ and\ z.$

Such that:

$x + y + z = 140$

Make z the subject

$z = 140 -x - y$

For their product to be maximum, we have:

$f(x,y,z) = xyz$

Substitute $z = 140 -x - y$ in $f(x,y,z) = xyz$

$f(x,y) = xy(140 - x - y)$

Open bracket

$f(x,y) = 140xy - x^2y - xy^2$

Differentiate w.r.t x and y

$f_x=140y - 2xy - y^2$

$f_y=140x - x^2 - 2xy$

Since the products are maximum, then $f_x = f_y = 0$

For $f_x=140y - 2xy - y^2$

$140y - 2xy - y^2 = 0$

Factorize:

$y(140 - 2x - y) = 0$

Split

$y = 0\ or\ 140 - 2x - y = 0$

Make y the subject

$y = 0\ or\ y = 140 - 2x$

For $f_y=140x - x^2 - 2xy$

$140x - x^2 - 2xy = 0$

---------------------------------------------------

Substitute y = 0

$140x - x^2 -2x*0 = 0$

$140x - x^2 = 0$

Factorize

$x(140 - x)= 0$

$x = 0\ or\ 140-x = 0$

$x = 0\ or\ x = 140$

---------------------------------------------------

Substitute $y = 140 - 2x$

$140x - x^2 - 2xy = 0$

$140x - x^2 - 2x(140 - 2x) = 0$

$140x - x^2 - 280x + 4x^2 = 0$

Re-arrange

$4x^2 -x^2 +140x - 280x = 0$

$3x^2 -140x = 0$

Factor x out

$x(3x - 140) = 0$

Divide through by x

$3x - 140 = 0$

$3x = 140$

$x = \frac{140}{3}$

Recall that: $y = 140 - 2x$

$y = 140 - 2 * \frac{140}{3}$

$y = 140 - \frac{280}{3}$

Take LCM

$y = \frac{140*3-280}{3}$

$y = \frac{140}{3}$

Recall that:

$z = 140 -x - y$

$z = 140 - \frac{140}{3} - \frac{140}{3}$

Take LCM

$z = \frac{3 * 140- 140 - 140}{3}$

$z = \frac{140}{3}$

Hence, the numbers are:

$\frac{140}{3}, \frac{140}{3}, \frac{140}{3}$

8 0

2 years ago

Practice Skills_ Simplifying Inequality1. 3( 1/2 - y) = 3/5 + 15y. What isthe solution to the given inequality?

Angelina_Jolie [31]

3( 1/2 - y) = 3/5 + 15y

Applying distributive property:

3*1/2 - 3y = 3/5 + 15y

3/2 - 3y = 3/5 + 15y

3/5 is adding on the right, then it will subtract on the left

3y is adding on the left, then it will subtract on the right

3/2 - 3/5 = 15y + 3y

15/10 - 6/10 = 18y

9/10 = 18y

18 is multiplying on the right, then it will divide on the left

9/10*1/18 = y

1/10*1/2 = y

1/20 = y

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10 months ago

Which of the following choices lists the values of the side longths of a triangle with 45-45-90 degree angles and a hypotonuso -

Ivenika [448]

Answer:

D 12rad2 12rad2 24

Step-by-step explanation:

3 0

2 years ago

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