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elena-14-01-66 [18.8K]
2 years ago
7

ANSWER THESE QUESTIONS FOR 70 POINTS I NEED THESE PLEASE

Mathematics
2 answers:
Leto [7]2 years ago
8 0
1) choice 3
2) commutative property
3) 12x + 8x -3x
common factor of x
x(12+8-3)
or
4x(3+2)-3x
S_A_V [24]2 years ago
5 0

Note: I don't know how to do the first 2 questions but the 3rd question I know. PLEASE FIRST LOOK AT THE EXPLANATION. WE ARE NOT HERE TO GIVE OUT ANSWERS, BUT TO HELP YOU.

Step-by-step explanation:

Step 1. IGNORE THE X

Step 2. add 12 and 8 (equals 20)

Step 3. Subtract 3 from 20 (equals 17).

Step 4. Now add the x to 17

Solution: 17x

Your welcome :)

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Which numbers below belong to the inequality check all that apply x/6 greater than equal to 9
grandymaker [24]
X/6 >= 9
x >= 6 x 9
x >= 54

Therefore, 60, 72 and 54 satisfies the inequality.
6 0
3 years ago
What is the sum and the product of X to the power of 2, and X
melomori [17]

Answer:

The sum is x^2 + x, the product is x^3.

Step-by-step explanation:

Adding x^2 and x leaves no like terms, so no simplification is required.

Multiplying gives x^2*x, which is x*x*x, which is then x^3

3 0
3 years ago
Given: AE ≅ CE ; DE ≅ BE Prove: ABCD is a parallelogram. Parallelogram A B C D is shown. Diagonals are drawn from point A to poi
nikklg [1K]

Answer:

The proof is below

Step-by-step explanation:

Given a parallelogram ABCD. Diagonals AC and BD intersect at E. We have to prove that AE is congruent to CE and BE is congruent to DE i.e diagonals of a parallelogram bisect each other.

In ΔACD and ΔBEC

AD=BC              (∵Opposite sides of a parallelogram are equal)

∠DAC=∠BCE       (∵Alternate angles)

∠ADC=∠CBE        (∵Alternate angles)

By ASA rule, ΔACD≅ΔBEC

By CPCT(Corresponding Parts of Congruent triangles)

AE=EC and DE=EB

Hence, AE is conruent to CE and BE is congruent to DE

6 0
2 years ago
What is 11% of 650 please?
Debora [2.8K]
578.5 is your answer.

take 650 x .11 and you get 71.5.
take 650 - 71.5 = 578.5
6 0
3 years ago
Find the difference quotient off, that is, find fly+h)-f(x) h h#0, for the following function. Be sure to simplify. f(x) = x^2 -
Sloan [31]

The difference quotient for the function f(x) is h+2x-7

Given :

Difference quotient formula

\frac{\left(f\left(x+h\right)-f\left(x\right)\right)}{h}

Given function f(x) = x^2 - 7x + 8

find the difference quotient using the formula

first we find out f(x+h) using given f(x)

replace x with x+h

f(x) = x^2 - 7x + 8 \\f(x+h)=\mathrm{ }\left(x+h\right)^2-7\left(x+h\right)+8\\Expand \; and \; simplify\\f(x+h)=x^2+2xh+h^2-7\left(x+h\right)+8\\f(x+h)=x^2+2xh+h^2-7x-7h+8

Now replace it in our formula and also replace f(x)

\frac{\left(f\left(x+h\right)-f\left(x\right)\right)}{h}\\ \frac{x^2+2xh+h^2-7x-7h+8-(x^2 - 7x + 8)}{h} \\\frac{x^2+2xh+h^2-7x-7h+8-x^2 + 7x - 8}{h} \\\\\frac{h^2+2xh-7h}{h}\\factor \; out \; h\\\frac{h\left(h+2x-7\right)}{h}\\h+2x-7

Learn more :brainly.com/question/23630564

3 0
3 years ago
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