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3 years ago

Which expression is a factor of 36x2−9?

Mathematics

1 answer:

Nataly_w [17]3 years ago

4 0

Answer:

18x - 9

Step-by-step explanation:

Factor the common factor of 9 first which gives $9(4x^{2} -1)$

$4x^{2} - 1$ is the difference of two squares and factors into (2x + 1)(2x - 1)

The complete factorization of $36x^{2} -9$ is 9(2x + 1)(2x - 1).

So 9(2x - 1) = 18x - 9 is a factor of the original expression.

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100 POINTS PRE-CALCULUS

Sonja [21]

Answer:

not sure for the 1st one but pretty sure 2nd one is B

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

I need help with this as soon as possible!

Kay [80]

Answer:

1. -3/6 is negative, because it descends by 3 and goes over by 6.

2. My first answer literally gives the keyword negative, therefore it's a negative line because it has a negative slope.

1. -8/0 is undefined, because there is a rise but there is no run, which also means that it's a:

2. vertical line

1. -5/-10 simplifies to 5/10 or 1/2, which is positive because it rises by 5(or 1) and runs over by 10(or 2).

2. Thus, this means that it's a positive line since it has a positive slope.

1. 0/-2 is zero, because when you actually solve the equation it'll equal 0.

2. This means that it'll have a horizontal line since there is no rise but there is a run only.

8 0

2 years ago

5-52: the first card selected from a standard 52-card deck is a king. a. if it is returned to the deck, what is the probability

Ksivusya [100]

Calculating the likelihood of experiments happening is one of the branches of mathematics known as probability.

The probability of getting a king card is 1/13 or 0.077.

<h3>What is meant by probability?</h3>

A probability is a numerical representation of the likelihood or chance that a specific event will take place. Both proportions ranging from 0 to 1 and percentages ranging from 0% to 100% can be used to describe probabilities.

Given: Total number of probability - 52

Now, the first selected card is king and it is returned to the deck.

So it contains no effect on the second selection card.

Then, we have to estimate probability to obtain a king

probability = favourable outcomes for a king / total possible outcomess

= 4 king cards / 52 cards in total

= 4 / 52 = 1 / 13

The probability of getting a king card is 1 / 13 or 0.077

Therefore, the correct answer is option B. 1/13, or 0.077.

The complete question is:

The first card selected from a standard 52-card deck was a king. It isreturned to the deck, what is the probability that a king will be drawn on the second selection?

A. 1/4 or 0.25

B. 1/13, or 0.077

C. 12/13, or 0.923

D. 1/3 or 0.33

E. None of the above

To learn more about probability refer to:

brainly.com/question/13604758

#SPJ4

5 0

1 year ago

BRAINLIEST ASAP! PLEASE HELP ME :)

Ivenika [448]

See above explanation

I am joyous to assist you anytime.

5 0

3 years ago

The taxi and takeoff time for commercial jets is a random variable x with a mean of 8.3 minutes and a standard deviation of 3.3

In-s [12.5K]

Answer:

a) There is a 74.22% probability that for 37 jets on a given runway, total taxi and takeoff time will be less than 320 minutes.

b) There is a 1-0.0548 = 0.9452 = 94.52% probability that for 37 jets on a given runway, total taxi and takeoff time will be more than 275 minutes.

c) There is a 68.74% probability that for 37 jets on a given runway, total taxi and takeoff time will be between 275 and 320 minutes.

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a random variable X, with mean $\mu$ and standard deviation $\sigma$ , a large sample size can be approximated to a normal distribution with mean $\mu$ and standard deviation $\frac{\sigma}{\sqrt{n}}$ .

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

The taxi and takeoff time for commercial jets is a random variable x with a mean of 8.3 minutes and a standard deviation of 3.3 minutes. This means that $\mu = 8.3, \sigma = 3.3$ .

(a) What is the probability that for 37 jets on a given runway, total taxi and takeoff time will be less than 320 minutes?

We are working with a sample mean of 37 jets. So we have that:

$s = \frac{3.3}{\sqrt{37}} = 0.5425$

Total time of 320 minutes for 37 jets, so

$X = \frac{320}{37} = 8.65$

This probability is the pvalue of Z when $X = 8.65$ . So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{8.65 - 8.3}{0.5425}$

$Z = 0.65$

$Z = 0.65$ has a pvalue of 0.7422. This means that there is a 74.22% probability that for 37 jets on a given runway, total taxi and takeoff time will be less than 320 minutes.

(b) What is the probability that for 37 jets on a given runway, total taxi and takeoff time will be more than 275 minutes?

Total time of 275 minutes for 37 jets, so

$X = \frac{275}{37} = 7.43$

This probability is subtracted by the pvalue of Z when $X = 7.43$

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{7.43 - 8.3}{0.5425}$

$Z = -1.60$

$Z = -1.60$ has a pvalue of 0.0548.

There is a 1-0.0548 = 0.9452 = 94.52% probability that for 37 jets on a given runway, total taxi and takeoff time will be more than 275 minutes.

(c) What is the probability that for 37 jets on a given runway, total taxi and takeoff time will be between 275 and 320 minutes?

Total time of 320 minutes for 37 jets, so

$X = \frac{320}{37} = 8.65$

Total time of 275 minutes for 37 jets, so

$X = \frac{275}{37} = 7.43$

This probability is the pvalue of Z when $X = 8.65$ subtracted by the pvalue of Z when $X = 7.43$ .

So:

From a), we have that for $X = 8.65$ , we have $Z = 0.65$ , that has a pvalue of 0.7422.

From b), we have that for $X = 7.43$ , we have $Z = -1.60$ , that has a pvalue of 0.0548.

So there is a 0.7422 - 0.0548 = 0.6874 = 68.74% probability that for 37 jets on a given runway, total taxi and takeoff time will be between 275 and 320 minutes.

7 0

3 years ago