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3 years ago

Which of these data sets could best be displayed on a dot plot?

Mathematics

2 answers:

7nadin3 [17]3 years ago

5 0

Answer:

Number 2

Step-by-step explanation:

The numbers are close to each other. (Only goes from 721-730). The dot plot line will be smaller.

alexandr1967 [171]3 years ago

3 0

The answer is number two, 721,722 and more on

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Ten times the sum of half a number and 6 is 8.

Sedaia [141]

That would be

$10( \frac{1}{2} n + 6) = 8$
$\frac{1}{2} n+6= \frac{8}{10}$
$.5n + 6 = .8$
$.5n = -5.2$
$n=-2.6$

Hope that helps :)

8 0

4 years ago

The window is 60 inches wide. What is the width of the window in feet.

blsea [12.9K]

Answer:

5feet

Step-by-step explanation:

1 foot= 12 inches

1 inches = 1/12 feet

60 inches= 60x1/12= 5 feet

8 0

3 years ago

a number machine uses a rule to charge input numbers into output numbers. this number machine charged 4 into 16, 5 into 20, and

DaniilM [7]

Answer:

Step-by-step explanation:

The function that we have in this is f(x) = 4x. We can see this in 4 * 4 = 16, 5 * 4 = 20 and 6 * 4 = 24. Therefore, following the pattern, 7 * 4 = 28.

6 0

3 years ago

When finding percentiles, if the locator L is not a whole number, one procedure is to interpolate so that a locator of 23.75,

inessss [21]

Answer:

The answer is "94"

Step-by-step explanation:

Given data:

51,54,64,68,72,74,76,83,94,94,99

Find:

$P_{75}=?P_{75}= (\frac{75(n+1)}{100})^{th} \ \ observation\\\\$

$= (\frac{75(11+1)}{100})^{th} \ \ observation\\\\= (\frac{75(12)}{100})^{th} \ \ observation\\\\= (\frac{75 \times 12}{100})^{th} \ \ observation\\\\= (\frac{900}{100})^{th} \ \ observation\\\\= 9^{th} \ \ observation\\\\= 9^{th} \ number \ is = 94$

7 0

3 years ago

A segment can have more than one bisector.<br> True<br> False

insens350 [35]

<span>Can a Segment have more than one bisector. Yes A segment can have more than one bisector. For every line segment, there is one perpendicular bisector that passes through the midpoint. There are infinitely many bisectors, but only one perpendicular bisector for any segment.</span>

4 0

3 years ago