Find x in the given figures.

Mathematics

1 answer:

marin [14]3 years ago

4 0

Answer:

$\large\boxed{X=\sqrt{12}\ in=2\sqrt3\ in}$

Step-by-step explanation:

ΔADC and ΔCBD are similar. Therefore the corresponding sides are in proportion:

$\dfrac{AD}{CD}=\dfrac{CD}{DB}$

We have

AD = 2, CD = X, DB = 6.

Substitute:

$\dfrac{2}{X}=\dfrac{X}{6}$ <em>cross multiply</em>

$X^2=(2)(6)\\\\X^2=12\to X+\sqrt{12}$

$\sqrt{12}=\sqrt{4\cdot3}=\sqrt4\cdot\sqrt3=2\sqrt3$

You might be interested in

PLEASE HELP!!! 14 POINTS!

Pepsi [2]

Area=1/2bh

add them
(1/2)ab+(1/2)c^2+(1/2)ab=
ab+(1/2)c^2
ab+(1/2)(a^2+b^2)
not sure which option to pick there are different preferences on what counts as 'simplified'

4. find area
area=LW
area=105*45=4725
depends on the area of the signs
answer is
4725/(areaof1sign)
anyway, round down your answer because you will have an incomplete sign if you don't

5. area=pir^2
1/2 of it is
area=1/2pir^2
area=(1/4)^2pir^2
area=pi((1/4)r)^2
the radius is now 1/4 of what it was originally, meaning that the diameter is also 1/4 of what it is now
we need to know diamater
answer is 1/4 of current diameter

3. unclear

4. area of 1 sign not given, answer is 4725/(areaof1sign), rounded DOWN to nearest integer

5. (404 error, diameter not found) answer is 1/4 of current diameter

8 0

3 years ago

Match each of the trigonometric expressions below with the equivalent non-trigonometric function from the following list. Enter

Levart [38]

Answer:

Match each of the trigonometric expressions below with theequivalent non-trigonometric function from the following list.Enter the appropiate letter(A,B, C, D or E)in each blank

A . tan(arcsin(x/8))

B . cos (arsin (x/8))

C. (1/2)sin (2arcsin (x/8))

D . sin ( arctan (x/8))

E. cos (arctan (x/8))

These are the spaces to fill out :

.. ..........x/64 (sqrt(64-x^2))

.............x/sqrt(64+x^2)

.............sqrt(64-x^2)/8

..............x/sqrt(64-x^2)

..............8/sqrt(64+x^2)

A. ........tan(arcsin(x/8)) =......x/sqrt(64-x^2)