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Nutka1998 [239]
3 years ago
8

Find x in the given figures.

Mathematics
1 answer:
marin [14]3 years ago
4 0

Answer:

\large\boxed{X=\sqrt{12}\ in=2\sqrt3\ in}

Step-by-step explanation:

ΔADC and ΔCBD are similar. Therefore the corresponding sides are in proportion:

\dfrac{AD}{CD}=\dfrac{CD}{DB}

We have

AD = 2, CD = X, DB = 6.

Substitute:

\dfrac{2}{X}=\dfrac{X}{6}             <em>cross multiply</em>

X^2=(2)(6)\\\\X^2=12\to X+\sqrt{12}

\sqrt{12}=\sqrt{4\cdot3}=\sqrt4\cdot\sqrt3=2\sqrt3

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