Question

Find x in the given figures.

Answer 1

Answer:

$\large\boxed{X=\sqrt{12}\ in=2\sqrt3\ in}$

Step-by-step explanation:

ΔADC and ΔCBD are similar. Therefore the corresponding sides are in proportion:

$\dfrac{AD}{CD}=\dfrac{CD}{DB}$

We have

AD = 2, CD = X, DB = 6.

Substitute:

$\dfrac{2}{X}=\dfrac{X}{6}$             cross multiply

$X^2=(2)(6)\\\\X^2=12\to X+\sqrt{12}$

$\sqrt{12}=\sqrt{4\cdot3}=\sqrt4\cdot\sqrt3=2\sqrt3$