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Nutka1998 [239]
4 years ago
8

Find x in the given figures.

Mathematics
1 answer:
marin [14]4 years ago
4 0

Answer:

\large\boxed{X=\sqrt{12}\ in=2\sqrt3\ in}

Step-by-step explanation:

ΔADC and ΔCBD are similar. Therefore the corresponding sides are in proportion:

\dfrac{AD}{CD}=\dfrac{CD}{DB}

We have

AD = 2, CD = X, DB = 6.

Substitute:

\dfrac{2}{X}=\dfrac{X}{6}             <em>cross multiply</em>

X^2=(2)(6)\\\\X^2=12\to X+\sqrt{12}

\sqrt{12}=\sqrt{4\cdot3}=\sqrt4\cdot\sqrt3=2\sqrt3

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Mademuasel [1]
If Triangle ABC is similar to triangle DEF, then ∠A is congruent to ∠D, ∠B is congruent to ∠E, and ∠C is congruent to ∠F.

If ∠E = 40°, then ∠B = 40°.

There are 180° in a triangle. If ∠A = 35° and ∠B = 40°, then ∠C = 180° - 35° - 40°.

180 - 35 - 40 = 105°
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8 0
3 years ago
Write the following equation in standard form : 8/7x^3 + x^4 + 6x +1
Leokris [45]

Answer:

  x^4 +8/7x^3  + 6x +1

Step-by-step explanation:

8/7x^3 + x^4 + 6x +1

Standard from is from the largest power to the smallest power

  x^4 +8/7x^3  + 6x +1

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4 years ago
Add 1/8 + 3/8<br><br> A. 3/64<br> B. 4/64<br> C. 4/16<br> D. 4/8
Luden [163]

the answer is........ D

7 0
3 years ago
2(x-5)=10 but the pemdas is backwards
ale4655 [162]

Answer:

2 (x-5) = 10

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Step-by-step explanation:

8 0
3 years ago
In a group of 100 students, 60 are freshman, 55 are female, and 22 are female freshman. Find the probability that a student pick
tatyana61 [14]

Answer:

93/100

Step-by-step explanation:

In a group of 100 students, 60 are freshman, 55 are female, and 22 are female freshman. Find the probability that a student picked from this group at random is either a freshman or female

Number of Freshman = 60

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Number of Freshman female 22

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The probability that a student picked from this group at random is either a freshman or female

Thus P(freshman or female) = 60/100 + 55/100 - 22/100 = 93/100

3 0
3 years ago
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