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Kipish [7]
4 years ago
7

Someone help me with finding the similarity statement and ratios of the side lengths cuz idk if it’s similar

Mathematics
1 answer:
andreyandreev [35.5K]4 years ago
5 0

When triangles are similar, ratios of corresponding side lengths are the same. The side lengths you know are CD, DU, VW, WU. (You also know CU, but you do not know the corresponding length VU.)

The ratios can be formed in any convenient way, but it is already clear that the triangles are not similar. CD = 73 is a prime number, and neither DU nor VW is a multiple of that. For example, ...

... CD/VW = 73/84 ≠ 48/55 = DU/WU

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For some postive value of Z, the probability that a standardized normal variable is between 0 and Z is 0.3770. The value of Z is
Talja [164]

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1.16

Step-by-step explanation:

Given that;

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P(Z < z)-P(Z < 0) = 0.3770

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SO to determine the value of z for which it is equal to 0.877, we look at the

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8 0
3 years ago
Conner and Jana are multiplying (3⁵6⁸)(3⁹6¹⁰).
ad-work [718]
<h3>Conner work is correct. Jana work is wrong</h3>

<em><u>Solution:</u></em>

<em><u>Given that,</u></em>

<em><u>Conner and Jana are multiplying:</u></em>

(3^56^8)(3^96^{10})

Given Conner's work is:

(3^56^8)(3^96^{10}) = 3^{5+9}6^{8+10} = 3^{14}6^{18}

We have to check if this work is correct

Yes, Conner work is correct

From given,

(3^56^8)(3^96^{10})\\\\3^5 \times 6^8 \times 3^9 \times 6^{10}

Use the following law of exponent

a^m \times a^n = a^{m+n}

Therefore,

3^5 \times 6^8 \times 3^9 \times 6^{10} = 3^5 \times 3^9 \times 6^8 \times 6^{10} = 3^{5+9} \times 6^{8+10} = 3^{14} \times 6^{18}

<em><u>Given Jana's work is:</u></em>

(3^56^8)(3^96^{10}) = 3^{5.9}6^{8.10} = 3^{45}6^{80}

This is incorrect

The powers of same base has to be added. But here, powers are multiplied which is wrong

7 0
3 years ago
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