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DochEvi [55]
3 years ago
11

How many km is 250 m?

Chemistry
1 answer:
Alex_Xolod [135]3 years ago
4 0
There are 0.25 kilometers in 250 meters
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What’s is the percent composition by mass of oxygen in magnesium oxide , Mg0
Advocard [28]

Answer:

40%

Explanation:

We'll begin by obtaining the molar mass of MgO. This is illustrated below:

Molar Mass of MgO = 24 + 16 = 40g/mol

Observing the formula MgO, we have 1 atom of O in it.

The percentage composition by mass of oxygen in MgO is given by:

Mass of O/Molar Mass of MgO x 100

= 16/40 x 100 = 40%

6 0
3 years ago
What is the formula for the stable binary ionic compound formed between Barium and Oxygen?
xeze [42]

Answer: a. BaO

Explanation:

For formation of a neutral ionic compound, the charges on cation and anion must be balanced. The cation is formed by loss of electrons by metals and anions are formed by gain of electrons by non metals.

Here element barium is having an oxidation state of +2 called as Ba^{2+} cation and O^{2-} is an anion with oxidation state of -2. Thus they combine and their oxidation states are exchanged and written in simplest whole number ratios to give neutral BaO

3 0
3 years ago
What is the difference between the physical and the life sciences?<br> at least 1 sentence pls
hram777 [196]

Answer:

Physical science is concerned with the study of natural, non living objects and life science is about living things.

Explanation:

I had fun answering this question.

5 0
3 years ago
Read 2 more answers
The photodissociation of ozone by ultraviolet light in the upper atmosphere is a first-order reaction with a rate constant of 1.
atroni [7]

Answer:

[O₃]= 8.84x10⁻⁷M  

Explanation:

<u>The photodissociation of ozone by UV light is given by:</u>

O₃ + hν → O₂ + O (1)

<u>The first-order reaction of the equation (1) is:</u>

rate = k [O_{3}] = - k \frac{\Delta [O_{3}]}{\Delta t} (2)

<em>where k: is the rate constant and Δ[O₃]/Δt: is the variation in the ozone concentration with time, and the negative sign is by the decrease in the reactant concentration </em>    

<u>We can get the following expression of the </u><u>first-order integrated law</u><u> of the reaction (1), by resolving the equation (2):</u>

[O_{3}]_{t} = [O_{3}]_{0} \cdot e^{-kt} (3)

<em>where [O₃](t): is the ozone concentration in the elapsed time and [O₃]₀: is the initial ozone concentration</em>

We can calculate the initial ozone concentration using equation (3):  

[O_{3}]_{t} = 5.0 \cdot 10^{-3}M \cdot e^{-(1.0\cdot 10^{-5}s^{-1}) (\frac{10d \cdot 24h \cdot 3600 s}{1d \cdot 1h})} = 8.84 \cdot 10^{-7}M

So, the ozone concentration after 10 days is 8.84x10⁻⁷M.

I hope it helps you!                    

3 0
4 years ago
How does William Jennings Bryan respond to the criticism that the free and unlimited coinage of silver will disrupt ""business i
kifflom [539]

Answer:

He responded by saying their business definition was far too narrow.

Explanation:

Williams Bryan relates the battle for free silver with the revolution in the United States.

His iconic "Cross of Gold" address ignited the Democratic National Convention in 1896 where he begged the american people not to be "crucified on the cross of gold." He was said this because of the Republicans plan to introduce a firm gold standard and abolish silver coinage.

3 0
3 years ago
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