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TEA [102]
3 years ago
6

37 moles of manganese bromide how many molecules?

Chemistry
1 answer:
DerKrebs [107]3 years ago
8 0
214.746049. I converted between grams Manganese
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Which state removed a physician's license to practice medicine.
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i think thats right

4 0
3 years ago
the volume of gas in a container was originally 3.24L, while at standard pressure 1.00 atm. what will the volume be if the press
Simora [160]
Hello!

To solve this problem, we will use the Boyle's Law, which describes how pressure changes when volume changes and vice-versa. The equation for this law is the following one, and we'll clear for V2:

P1*V1=P2*V2 \\ \\ V2= \frac{P1*V1}{P2}= \frac{3,24 L * 1 atm}{1,20 atm}= 2,7 L

So, the final volume after increasing the pressure would be 2,7 L. That means that volume decreases when the pressure increases

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8 0
4 years ago
Use the standard enthalpies of formation for the reactants and products to solve for the ΔHrxn for the following reaction. (The
Rudiy27
<span>
1. Remember (sum of products) - (sum of reactants)
So ΔHrxn = 2 ΔHf [H2(g)] + ΔHf [Ca(OH)2(s)] - 2 ΔHf [H2O(l)] - ΔHf [Ca(s)]
= 2*0 + -986.09 kJ/mol - 2*(-285.8 kJ/mol) - 0

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8 0
3 years ago
Read 2 more answers
Propiedades quimicas de la plata​
timofeeve [1]
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7 0
3 years ago
How many mL of a 1 M NaOH solution are required to neutralize 100 mL of a 2 M H2SO4 solution?
Murljashka [212]

Answer : The volume of 1 M NaOH solution required are, 400 mL

Explanation :

To calculate the volume of base, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is H_2SO_4

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is NaOH.

We are given:

n_1=2\\M_1=2M\\V_1=100mL\\n_2=1\\M_2=1M\\V_2=?

Putting values in above equation, we get:

2\times 2M\times 100mL=1\times 1M\times V_2

V_2=400mL

Therefore, the volume of 1 M NaOH solution required are, 400 mL

5 0
3 years ago
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