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3 years ago

In the chemical reaction shown below how do you classify hydrogen and oxygen 2h2+o2→h2o

Chemistry

1 answer:

earnstyle [38]3 years ago

6 0

In the chemical reaction shown, 2H2 + O2→H2O, hydrogen and oxygen are called reactants.

A chemical reaction equation is has a left and a right hand side separated by an arrow.

The species on the left hand side "combine" to yield the specie(s) on the right hand side.

These species on the left hand side undergo breaking of bonds are rearrangement of atoms to give the species on the right hand side.

Hence, the species on the left hand side are called reactants because they combine with each other to give the species on the right hand side (products).

Learn more: brainly.com/question/17096236

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Explanation:

There is some info missing. I think this is the complete question.

Suppose a 250 mL flask is filled with 0.30 mol of N₂ and 0.70 mol of NO. The following reaction becomes possible:

N₂(g) +O₂(g) ⇄ 2 NO(g)

The equilibrium constant K for this reaction is 7.70 at the temperature of the flask. Calculate the equilibrium molarity of O₂. Round your answer to two decimal places.

Initially, there is no O₂, so the reaction can only proceed to the left to attain equilibrium. The initial concentrations of the other substances are:

[N₂] = 0.30 mol / 0.250 L = 1.2 M

[NO] = 0.70 mol / 0.250 L = 2.8 M

We can find the concentrations at equilibrium using an ICE Chart. We recognize 3 stages (Initial, Change, and Equilibrium) and complete each row with the concentration or change in the concentration.

N₂(g) +O₂(g) ⇄ 2 NO(g)

I 1.2 0 2.8

C +x +x -2x

E 1.2+x x 2.8 - 2x

The equilibrium constant (K) is:

$K=7.70=\frac{[NO]^{2}}{[N_{2}][O_{2}]} =\frac{(2.8-2x)^{2} }{(1.2+x).x}$

Solving for x, the positive one is x = 0.3601 M

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