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2 years ago

In the chemical reaction shown below how do you classify hydrogen and oxygen 2h2+o2→h2o

Chemistry

1 answer:

earnstyle [38]2 years ago

6 0

In the chemical reaction shown, 2H2 + O2→H2O, hydrogen and oxygen are called reactants.

A chemical reaction equation is has a left and a right hand side separated by an arrow.

The species on the left hand side "combine" to yield the specie(s) on the right hand side.

These species on the left hand side undergo breaking of bonds are rearrangement of atoms to give the species on the right hand side.

Hence, the species on the left hand side are called reactants because they combine with each other to give the species on the right hand side (products).

Learn more: brainly.com/question/17096236

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Solution :

For the reaction :

$\text{TrisH}^+ + H_2O \rightarrow \text{Trish}^- + H_3O^+$

we have

$Ka = \frac{[\text{Tris}^- \times H_3O]}{\text{Tris}^+}$

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So to reach $\text{pH} = 7.8 (\text{pOH}= 14-7.8=6.2)$ , one must have the $\text{OH}^-$ concentration of the :

$\text{[OH}^-]=10^{-pOH} = 6.31 \times 10^{-7} \text{ moles of base}$

So we can add enough of 1 M NaOH in order to neutralize the acid that is calculated above and also adding the calculated base.

$\text {n NaOH}=1.29 \times 10^{-5}+6.31 \times 10^{-7}$

$= 1.35 \times 10^{-5} \text{ moles}$

Volume NaOH $= 1.35 \times 10^{-5} \text{ moles} \times \frac{1000 \text{ mL}}{1 \text{ mol}} = 0.0135 \text{ mL}$

Tris mass $H^+ = 0.02 \text{ mol} \times 157.6 \text{ g/mol}=3.152 \text{ g}$

Now to prepare the said solution we must mix:

$3.152 \text{ g Tris H} + 0.0135 \text{ mL NaOH} \ 1 M$ gauge to 1000 mL with water.

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