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Cloud [144]
4 years ago
13

After mitosiis how many chromosomes willl there be in the dogs new body cells

Chemistry
1 answer:
erastova [34]4 years ago
3 0
The number should be the same as the diploid (2n) number—that is, the number usually present in the rest of the body's cells.
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A smoke sample contains dust particles and several different gases, which have different combinations of molecules. the dust par
Vsevolod [243]
The sample of smoke described above can be described as a heterogeneous mixture. This type of mixture do not have uniform properties and composition. So, getting a certain small sample would not represent the whole mixture since it does not have uniform composition. 
7 0
3 years ago
What is the weight in grams of 3.36 x 10^23 molecules of copper sulfate
Llana [10]

Answer:

m=89.0g

Explanation:

Hello!

In this case, since we are given the formula units (molecules) of copper sulfate, it is possible to compute the moles of this compound via the Avogadro's number:

n=3.36x10^{23}molecules*\frac{1mol}{6.022x10^{23}molecules}\\\\n=0.558mol

Now, given the molar mass of copper sulfate which is 159.60 g/mol, the required mass in grams turns out:

m=0.558mol*\frac{159.60g}{1mol}\\\\m=89.0g

Best regards!

5 0
3 years ago
How many atoms of iodine are in 12.75g of CaI2? Hint. How many Iodines are there in one CaI2 particle?
xenn [34]

Answer:

5.225x10^{22}atoms\ I

Explanation:

Hello!

In this case, since 12.75 g of calcium iodide has the following number of moles (molar mass = 293.89 g/mol):

n_{CaI_2}=12.75gCaI_2*\frac{1molCaI_2}{293.89gCaI_2}=0.0434molCaI_2

In such a way, since 1 mole of calcium iodide contains 2 moles of atoms of iodine, and one mole of atoms of iodine contains 6.022x10²³ atoms (Avogadro's number), we compute the resulting atoms as shown below:

atoms\ I=0.0434molCaI_2*\frac{2molI}{1molCaI_2} *\frac{6.022x10^{23}atoms\ I}{1molI} \\\\atoms\ I = 5.225x10^{22}atoms\ I

Best regards!

4 0
3 years ago
A student titrated 20 ml of 0.410 m hcl with 0.320 m naoh. determine the volume of naoh needed at equivalence point
Aleksandr-060686 [28]

Answer:

25.6mL NaOH

Explanation:

We are given the Molarity of the solution (\frac{moles}{liters}) and the volume of the solution (.02L).

By multiplying the two together, we can find the moles of solution that are reacted with HCl.

moles = \frac{.410 moles}{L} *.02L

This gives us .0082 moles of HCl.

We then find the moles of NaOH that are needed to react with the HCl using the equation.

HCl + NaOH = NaCl + H_{2} O

As HCl and NaCl have a 1:1 ratio, we need .0082 mol of NaOH.

Dividing this value by the Molarity of the solution

\frac{.0082mol}{.320mol/L}

Gives us the answer, in Liters (.0256), which we can then divide by 100 convert to mL.

3 0
3 years ago
Which two terms relate and why? Atom, Amu, Element
nika2105 [10]

Atoms and element do relate with each other.

<h3><u>Explanation:</u></h3>

Atoms are defined as the smallest particle of an element which cannot be divided further keeping its physical and chemical properties intact, and they take part in a chemical reaction.

Elements are defined as the substances that are components of matter and cannot be further divided into simpler substances.

AMU or the Atomic mass unit is defined as a unit that is used to express atomic mass and is equal to mass of a hydrogen ion.

Elements are actually formed of atoms that are present in nature and atoms do form elements and even compounds. So they are inter related with each other.

7 0
3 years ago
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