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3 years ago

What are the three sub-types of convergent plate boundaries

1 answer:

3 0

<span>Oceanic-oceanic convergent plate boundary. 2 Continental convergent plate boundary. 3 Oceanic-continental convergent plate boundary.</span>

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What are the chemical symbols for the two elements found in iron oxide

Gnom [1K]

For Iron: $Fe$

For Oxygen: $O$

These are the two chemical symbols for the two elements found in Iron Oxide.

7 0

3 years ago

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What are the chemicals used to preserve food and give it color and flavor

Lelechka [254]

Answer:

Some of the chemicals used to preserve food and give it color are sodium nitrate, sodium benzoate, and propionate

Explanation:

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2 years ago

Information about tectonic plate boundaries has been primarily found by scientists studying data from

taurus [48]

Studying data from earthquakes!

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2 years ago

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The reaction C4H8(g)⟶2C2H4(g) C4H8(g)⟶2C2H4(g) has an activation energy of 262 kJ/mol.262 kJ/mol. At 600.0 K,600.0 K, the rate c

crimeas [40]

Answer : The rate constant at 785.0 K is, $1.45\times 10^{-2}s^{-1}$

Explanation :

According to the Arrhenius equation,

$K=A\times e^{\frac{-Ea}{RT}}$

or,

$\log (\frac{K_2}{K_1})=\frac{Ea}{2.303\times R}[\frac{1}{T_1}-\frac{1}{T_2}]$

where,

$K_1$ = rate constant at $600.0K$ = $6.1\times 10^{-8}s^{-1}$

$K_2$ = rate constant at $785.0K$ = ?

$Ea$ = activation energy for the reaction = 262 kJ/mole = 262000 J/mole

R = gas constant = 8.314 J/mole.K

$T_1$ = initial temperature = $600.0K$

$T_2$ = final temperature = $785.0K$

Now put all the given values in this formula, we get:

$\log (\frac{K_2}{6.1\times 10^{-8}s^{-1}})=\frac{262000J/mole}{2.303\times 8.314J/mole.K}[\frac{1}{600.0K}-\frac{1}{785.0K}]$

$K_2=1.45\times 10^{-2}s^{-1}$

Therefore, the rate constant at 785.0 K is, $1.45\times 10^{-2}s^{-1}$

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3 years ago

A container is filled with oxygen gas, and the pressure of

Amanda [17]

Answer:

77,007 Pa

Explanation:

Hello!

In this case, since the equivalence statement for atmospheres and pascals is:

1 atm = 101,325 Pa

We can set up the following conversion factor to obtain the pressure in pascals:

$0.760atm*\frac{101,325Pa}{1atm}\\\\=77,007Pa$

Best regards!

3 0

2 years ago