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3 years ago

5

A 5-kg chunk of amluminum and a 5-kg block of silver that are the same temperature have the same thermal energy true or false

1 answer:

Fynjy0 [20]3 years ago

8 0

Answer:

The thermal energy of an object is the total energy of the particles in a material. A 5-kg chunk of aluminum and a 5-kg block of silver that are at the same temperature have the same thermal energy. Heat flows from a higher temperature to a lower temperature.

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A chemist performs the same tests on two homogeneous white crystalline solids, A and B. The results are shown in the table below

Nookie1986 [14]

Solid A contains only Covalent bonds and solid B only contains Ionic bonds. I know this because the appearance, solubility, and conductivity of solid A describes Covalent bonds.

Explanation:

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3 years ago

A student mixes some water at room temperature with a white powder also at room temperature. The white powder disappears into th

Leya [2.2K]

Chemical change, because the white powder heated the water and caused a thermal reaction, and possibly gas was produced due to bubbles.

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3 years ago

The density of concentrated ammonia, which is 28.0% w/w nh3, is 0.899 g/ml. what volume of this reagent should be diluted to 1.0

vlada-n [284]

Answer: 2.4 ml

Solution :

Molar mass of $NH_3$ = 17 g/mole

Given,: 28% w/w of $NH_3$ solution means 28 g of ammonia in 100 g of solution.

Mass of solution = 100 g

Now we have to calculate the volume of solution.

$Volume=\frac{Mass}{Density}=\frac{100g}{0.899g/ml}=111.2ml$

Molarity : It is defined as the number of moles of solute present in one liter of solution.

$Molarity=\frac{n\times 1000}{V_s}$

where,

n = moles of solute $NH_3=\frac{\text {given mass}}{\text {molar mass}}=\frac{28}{17}=1.65moles$

$V_s$ = volume of solution in liter = 0.11 L

Now put all the given values in the formula of molarity, we get

$Molarity=\frac{1.65moles}{0.11L}=15mole/L$

Using molarity equation:

$M_1V_1=M_2V_2$

$15\times V_1=0.036\times 1.0\times 10^{3}$

$V_1=2.4ml$

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3 years ago

Use the IUPAC nomenclature rules to give the name for this compound - CrPO4.

MrRissso [65]

Answer:

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Explanation:

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3 years ago

27. The density of nickel is 8.91 g/cm3. How large a cube, in cm3, would contain 2.00 x 10^24 atoms of nickel? Use dimensional a

jok3333 [9.3K]

Answer : The volume of the cube is, $21.88cm^3$

Solution : Given,

Density of nickel = $8.91g/cm^3$

Number of nickel atoms = $2\times 10^{24}$

Molar mass of nickel = 58.7 g/mole

First we have to calculate the moles of nickel.

As, $6.022\times 10^{23}$ atoms form 1 mole of nickel

So, $2\times 10^{24}$ atoms form $\frac{2\times 10^{24}}{6.022\times 10^{23}}=3.321$ moles of nickel

The moles of nickel = 3.321 moles

Now we have to calculate the mass of nickel.

$\text{ Mass of Ni}=\text{ Moles of Ni}\times \text{ Molar mass of Ni}$

$\text{ Mass of Ni}=(3.321moles)\times (58.7g/mole)=194.94g$

The mass of nickel = 194.94 g

Now we have to calculate the volume of nickel.

$Density=\frac{Mass}{Volume}$

$8.91g/cm^3=\frac{194.94g}{Volume}$

$Volume=21.88cm^3$

Therefore, the volume of the cube is, $21.88cm^3$

4 0

3 years ago