Answer:
z = 110°
Step-by-step explanation:
Angles z and the one marked 70° form an linear pair, hence are supplementary.
z = 180° -70° = 110°
<h3>Angles where chords cross</h3>
The angle made by two chords is half the sum of the arcs intercepted by those chords. Here, that means ...
70° = 1/2(60° +x) ⇒ x = 140° -60° = 80°
The arc w completes the circle of 360°, so we have ...
w +x +79° +60° = 360° ⇒ w = 360° -219° = 141°
Finally, z is the average of w and 79°:
z = (w +79°)/2 = (141° +79°)/2 = 110° . . . as above
F is 5 because -1 and 1 are not web that makes 8 odd so f is 5
3,400 since 81,600÷24= 3,400.
Answer:
radius = 4 cm
Step-by-step explanation:
To find the length of the radius, we will follow the step below;
First, write down the formula for finding the volume of a cylinder
v=πr²h
where v is the volume of a cylinder
r is the radius and
h is the height of the cylinder
from the question given,
v=125.6 and h = 10 cm
we can now proceed to insert the values into the formula and solve for r
note that π is a constant which is equal to 3.14
v=πr²h
125.6 =3.14×r×10
125.6 =31.4 r
Divide both-side of the equation by 31.4
125.6/31.4 =31.4 r/31.4
4 = r
r =4 cm
The length of the radius = 4 cm
Answer:
![\left[\begin{array}{ccc}4&19&-5\\7&0&-14\end{array}\right] + \left[\begin{array}{ccc}-8&7&0\\-1&17&6\end{array}\right] = \left[\begin{array}{ccc}-4&26&-5\\6&17&-8\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D4%2619%26-5%5C%5C7%260%26-14%5Cend%7Barray%7D%5Cright%5D%20%2B%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-8%267%260%5C%5C-1%2617%266%5Cend%7Barray%7D%5Cright%5D%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-4%2626%26-5%5C%5C6%2617%26-8%5Cend%7Barray%7D%5Cright%5D)
Step-by-step explanation:
To add two matrices you just need to add the corresponding entries together. In this case, we have that:
![\left[\begin{array}{ccc}4&19&-5\\7&0&-14\end{array}\right] + \left[\begin{array}{ccc}-8&7&0\\-1&17&6\end{array}\right]=\left[\begin{array}{ccc}4-8&19+7&-5 + 0\\7-1&0+17&-14+6\end{array}\right] = \left[\begin{array}{ccc}-4&26&-5\\6&17&-8\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D4%2619%26-5%5C%5C7%260%26-14%5Cend%7Barray%7D%5Cright%5D%20%2B%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-8%267%260%5C%5C-1%2617%266%5Cend%7Barray%7D%5Cright%5D%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D4-8%2619%2B7%26-5%20%2B%200%5C%5C7-1%260%2B17%26-14%2B6%5Cend%7Barray%7D%5Cright%5D%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-4%2626%26-5%5C%5C6%2617%26-8%5Cend%7Barray%7D%5Cright%5D)
Then, we conclude that the sume of the two matrices is:
