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almond37 [142]
3 years ago
9

when a ball is dropped off a cliff in free fall, it has an acceleration of 9.8 m/s^2. what is its acceleration as it gets closer

to the ground
Physics
2 answers:
vazorg [7]3 years ago
7 0
Acceleration due to gravity is contract for the purposes of this question, so the acceleration would remain at 9.8 m/s^2
larisa [96]3 years ago
4 0

If the ball, the cliff, and the ground are all on the Earth, and everything is bathed in an ocean of air, then the ball's acceleration will decrease as it falls, because of the friction of air resistance.  If it has far enough to fall, it's possible that its acceleration may even become zero, and the ball settle on a constant speed (called "terminal velocity") before it hits the ground.

But until we get to College-level Physics and Engineering, we ALWAYS ignore that stuff, and assume NO AIR RESISTANCE.  The ball is in FREE FALL, and the ONLY force acting on it is the force of gravity.   We also assume that the distance of the fall is small enough so that the value of gravity is constant over the entire fall.

Under those assumptions, there's nothing present to change the acceleration of the falling ball.  It's 9.81 m/s² when it rolls off the edge of the cliff, and it's 9.81 m/s² when it hits the ground.

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assuming that voltage remains constant, what happpens to the current in a wire as its diameter decreases?
Nataly_w [17]
A larger diameter wire has lower resistance. A lower resistance wire produces less heat for a given current flowing through it.
6 0
4 years ago
A Chinook salmon can jump out of water with a speed of 6.70 m/s6.70 m/s . How far horizontally dd can a Chinook salmon travel th
aksik [14]

Answer:

R = 3.88 m

Explanation:

As the Chinook salmon leaves the water till it gets back into the water it is performing a projectile motion with the following parameters:

V₀ = Launch Speed = 6.7 m/s

θ = Launch Angle = 29°

R= Range of Projectile= Horizontal Distance Covered by Chinook salmon= ?

The value of the range of a projectile is given by the following formula:

R = (V₀² Sin 2θ)/g

R = [(6.7 m/s)² Sin {(2)(29°)}/(9.8 m/s²)]

R = [(6.7 m/s)² Sin (58°)/(9.8 m/s²)]

<u>R = 3.88 m</u>

8 0
4 years ago
Mass and Weight: What is the mass of an object that experiences a gravitational force of 685 N near Earth's surface where g
11Alexandr11 [23.1K]

Answer:

m = 69.9 kg

Explanation:

The mass and the weight of an object are two different quantities. Mass is basically the amount of matter that is present in a body. It remains same everywhere in the universe and measured in kilograms.

Weight is basically a force. It is the force by which earth attracts everything towards itself. The weight of an object changes from planet to planet, with the change in value of the gravitational acceleration (g).

Therefore, the relation between mass and weight of an object is given by the following formula:

W = mg

m = W/g

where,

m = mass = ?

W = Weight = 685 N

g = 9.8 m/s²

Therefore,

m = (685 N)/(9.8 m/s²)

<u>m = 69.9 kg</u>

4 0
3 years ago
A dolphin accelerates at -1.77 m/s2 for
Zepler [3.9K]

Answer:

-19.4 m

Explanation:

Given:

a = -1.77 m/s²

t = 3.33 s

v = -8.77 m/s

Find: Δx

Δx = vt − ½ at²

Δx = (-8.77 m/s) (3.33 s) − ½ (-1.77 m/s²) (3.33 s)²

Δx = -19.4 m

5 0
4 years ago
Which of these help create radio waves?
inysia [295]
The one that help create radio waves is :
Changing electric and magnetic fields applied at right angles

Radio waves are transverse wave, which means  that the oscillations occurring perpendicular to the direction of energy transfer

hope this helps
3 0
3 years ago
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