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Neporo4naja [7]
3 years ago
12

The density of mercury is 13.6 g/cm3 calculate the mass of 1 cm3 of mercury

Physics
1 answer:
7nadin3 [17]3 years ago
5 0

the mass of 1cm3 of mercury is 13.6g because

the formula of density is mass/volume and when paste the number in it. you get the answer

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12
Svet_ta [14]

Answer:

See below ~

Explanation:

An object will sink in water when its density is greater than that of water, which is 1 g/cm³.

Volume of the box is <u>1331 cm³</u>. (11³)

Maximum mass of sand will be 1331 g. [because 1331/1331 = 1 g/cm³]

  • Volume of sand = Mass of sand / Density of sand
  • Volume (sand) = 1331/3.5
  • Volume (sand) = 380.29 cm³

If the volume of sand is <u>greater than 380.29 cm³</u>, the box will sink in water.

6 0
3 years ago
Consider an electrical transformer has 10 loops on its primary coil and 20 loops on its secondary coil. What is the voltage in t
Arlecino [84]

Answer:

240 V

Explanation:

number of turns in primary coil, Np = 10

Number of loops in secondary coil, Ns = 20

Voltage in primary coil, Vp = 120 V

Let the voltage in secondary coil is Vs.

So, Vs / Vp = Ns / Np

Vs / 120 = 20 / 10

Vs / 120  = 2

Vs = 240 V

Thus, the voltage in secondary coil is 240 Volt.

4 0
3 years ago
Which change would cause the largest increase in a mountain climber’s gravitational potential energy?
3241004551 [841]
<span>carrying twice the weight and climbing twice as high</span>
5 0
4 years ago
Read 2 more answers
Exposure to a sufficient quantity of ultraviolet will redden the skin, producing erythema - a sunburn. The amount of exposure ne
ivann1987 [24]

Answer:

Energy = 7.83 x 10⁻¹⁹ J

Energy = 6.63 x 10⁻¹⁹ J

Explanation:

The energy of a photon in terms of wavelength can be calculated by the following formula:

Energy = \frac{hc}{\lambda}\\

where,

h = Plank's Constant = 6.63 x 10⁻³⁴ Js

c = speed of light = 3 x 10⁸ m/s

λ = wavelength of light

Now, for λ = 254 nm = 2.54 x 10⁻⁷ m:

Energy = \frac{(6.63\ x\ 10^{-34}\ Js)(3\ x\ 10^8\ m/s)}{2.54\ x\ 10^{-7}\ m}\\

<u>Energy = 7.83 x 10⁻¹⁹ J</u>

<u></u>

Now, for λ = 300 nm = 3 x 10⁻⁷ m:

Energy = \frac{(6.63\ x\ 10^{-34}\ Js)(3\ x\ 10^8\ m/s)}{3\ x\ 10^{-7}\ m}\\

<u>Energy = 6.63 x 10⁻¹⁹ J</u>

7 0
3 years ago
What work do you think is done when you carry a 20 N weight backpack for a 1000 m walk? will the work be positive, negative, or
dezoksy [38]

The work done is positive and is equal to 20000 J

<h3>What is work done?</h3>

Work done is defined as the product of force and the distance moved by the force.

Mathematically:

  • Work done = force * distance

The work done by the force = 20 * 1000 = 20000J

The work done is positive and is equal to 20000 J

Learn more about work done at: brainly.com/question/25923373

#SPJ1

8 0
2 years ago
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