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denpristay [2]
3 years ago
7

Does the sun make Gamma rays?what gives Infrared light?

Physics
1 answer:
Gnesinka [82]3 years ago
4 0
Sun fives off both of them
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A boxed 14.0 kg computer monitor is dragged by friction 5.50 m up along the moving surface of a conveyor belt inclined at an ang
adell [148]

Answer:

A boxed 14.0 kg computer monitor is dragged by friction 5.50 m up along the moving surface of a conveyor belt inclined at an angle of 36.9 ∘ above the horizontal. The monitor's speed is a constant 2.30 cm/s.

how much work is done on the monitor by (a) friction, (b) gravity

work(friction) = 453.5J

work(gravity) = -453.5J

Explanation:

Given that,

mass = 14kg

displacement length = 5.50m

displacement angle = 36.9°

velocity = 2.30cm/s

F = ma

work(friction) = mgsinθ .displacement

                      = (14) (9.81) (5.5sin36.9°)

                       = 453.5J

work(gravity)

= the influence of gravity oppose the motion of the box and can be pushing down, on the box from and angle of (36.9° + 90°)

= 126.9°

work(gravity) = (14) (9.81) (5.5cos126.9°)

                      = -453.5J

8 0
3 years ago
You're at rest in a hammock when a hungry mosquito sees an opportunity for lunch. A mild 2 m/s breeze is blowing. If the mosquit
valentinak56 [21]

Answer:

A) against the breeze at 2 m/s

Explanation:

Given that air is blowing at 2 m/s.An a mosquito eat lunch.If mosquito want to eat lunch he have to move opposite to the direction of air because air is blowing at 2 m/s.So we can say that mosquito have to move against the air.

But in we have to protect our self from mosquito because if any mosquito bite us then it may lead to fever .So the protection is very important from mosquito .

Therefore the answer is --

A

6 0
3 years ago
Two cars - Car A and Car B - drive in the same direction down a street. Car B is traveling at 30 m/s. Car A is traveling 20 m/s.
Darina [25.2K]

Answer:derp

Explanation:

8 0
3 years ago
The electric flux through a square-shaped area of side 5 cm near a very large, thin, uniformly-charged sheet is found to be 3\ti
deff fn [24]

Answer:

Explanation:

Given

side of square shape a=5\ cm

Electric flux \phi =3\times 10^{-5}\ N.m^2/C

Permittivity of free space \epsilon_0=8.85\times 10^{-12} \frac{C^2}{N.m^2}

Flux is given by

\phi =EA\cos \theta

where E=electric field strength

A=area

\theta=Angle between Electric field and area vector

E=\frac{\phi }{A\cos (0)}

E=\frac{3\times 10^{-5}}{25\times 10^{-4}\times \cos(0)}

E=0.012\ N/C

and Electric field  by a uniformly charged sheet is given by

E=\frac{\sigma }{2\epsilon_0}

where \sigma=charge density

=\frac{\sigma }{\epsilon_0}

\sigma =0.012\times 8.85\times 10^{-12}

\sigma =2.12\times 10^{-13}\ C/m^2    

5 0
3 years ago
What is 64 nanometers to m?
defon
\sf Hello!

\sf We\: know \:that,
\sf 1\: meter = \sf 10^{9} nm

\sf Then,

\sf Distance\: in \:m = \sf Distance\: in\: nm × \dfrac{\sf 1}{\sf 10^{9}}\: \sf m

⇒ \sf Distance\: in \:m = \sf 64 × 10^{-9} \:m

⇒ \sf Distance\: in\: m = \sf 6.4 × 10^{-8} \:m

~ \sf iCarl
3 0
3 years ago
Read 2 more answers
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