Physics - Damon, Wednesday, December 9, 2015 at 5:13am
F = k x
k = 2 g/6.1 cm
2.5g = (2g/6.1cm) x
x = 6.1 (2.5/2) cm
Answer:
decrease the height
Explanation:
height is directly proportional to the g.p.e
Answer:
The motion is over-damped when λ^2 - w^2 > 0 or when
> 0.86
The motion is critically when λ^2 - w^2 = 0 or when
= 0.86
The motion is under-damped when λ^2 - w^2 < 0 or when
< 0.86
Explanation:
Using the newton second law
k is the spring constante
b positive damping constant
m mass attached
x(t) is the displacement from the equilibrium position

Converting units of weights in units of mass (equation of motion)

From hook's law we can calculate the spring constant k

If we put m and k into the DE, we get

Denoting the constants
2λ =
= 
λ = b/0.215

λ^2 - w^2 = 
This way,
The motion is over-damped when λ^2 - w^2 > 0 or when
> 0.86
The motion is critically when λ^2 - w^2 = 0 or when
= 0.86
The motion is under-damped when λ^2 - w^2 < 0 or when
< 0.86
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