<u>Answer:</u> The equilibrium constant for the reaction is 54.47
<u>Explanation:</u>
The equilibrium constant is defined as the ratio of the concentration of products to the concentration of reactants raised to the power of the stoichiometric coefficient of each. It is represented by the term 
The given chemical equation follows:

The expression for equilibrium constant will be:
![K_{eq}=\frac{[HI]^2}{[H_2][I_2]}](https://tex.z-dn.net/?f=K_%7Beq%7D%3D%5Cfrac%7B%5BHI%5D%5E2%7D%7B%5BH_2%5D%5BI_2%5D%7D)
We are given:
![[HI]_{eq}=1.3544\times 10^{-2}M](https://tex.z-dn.net/?f=%5BHI%5D_%7Beq%7D%3D1.3544%5Ctimes%2010%5E%7B-2%7DM)
![[H_2]_{eq}=4.5647\times 10^{-3}M](https://tex.z-dn.net/?f=%5BH_2%5D_%7Beq%7D%3D4.5647%5Ctimes%2010%5E%7B-3%7DM)
![[I_2]_{eq}=7.378\times 10^{-4}M](https://tex.z-dn.net/?f=%5BI_2%5D_%7Beq%7D%3D7.378%5Ctimes%2010%5E%7B-4%7DM)
Putting values in above expression, we get:

Hence, the equilibrium constant for the reaction is 54.47
Answer:
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First, we have the ionic elements. This type of elements involved completely transferring of one ion to another in order to form a bond. There is also the type which forms the covalent bond which involves only sharing of the electrons. Those that exhibits the polar bonds and also the hydrogen bonding.
Answer:
The formula of the hydrate of the sodium sulfate is :
Explanation:
Mass of hydrated sodium sulfate = 40.15 gram
Mass of completely dehydrated sodium sulfate = 21.27 gram
Mass of water molecules present in hydrated sodium sulfate =x
40.15 gram = 21.27 gram + x (Law of conservation of mass)
x = 40.15 gram - 21.27 gram = 18.88 g
Moles of water = 
Moles of sodium sulfate =
Whole number ratio of sodium sulfate and water:
Sodium sulfate =
Water =
The formula of hydrate be 
So, the formula of the hydrate of the sodium sulfate is :