Answer:
16.16g of O2.
Explanation:
We'll begin by writing the balanced equation for the reaction. This is illustrated below:
4NH3 + 5O2 → 4NO + 6H2O
Next, we shall determine the mass of NH3 and O2 that reacted from the balanced equation. This is illustrated below:
Molar mass of NH3 = 14 + (3x1) = 17g/mol
Mass of NH3 from the balanced equation = 4 x 17 = 68g
Molar Mass of O2 = 16x2 = 32g/mol
Mass of O2 from the balanced equation = 5 x 32 = 160g.
From the balanced equation above,
68g of NH3 reacted with 160g of O2.
Now, we can calculate the mass of O2 that will be required to react completely with 6.87 g of NH3. This is illustrated below:
From the balanced equation above,
68g of NH3 reacted with 160g of O2
Therefore, 6.87g of NH3 will react with = (6.87 x 160)/68 = 16.16g of O2.
Therefore, 16.16g of O2 is needed for the reaction.
