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lana [24]
3 years ago
7

Select all of the statements that are true about a buffer solution. Select one or more: a. A buffer solution reacts with basic s

olutions. b. A buffer solution has a pH of 7. c. A buffer solution reacts with acidic solutions. d. A buffer solution always changes color when the pH changes. e. A buffer solution resists small changes in pH. Question 13 Not yet answered Marked out of 1.00 Not flaggedFlag question Question text At what point on the titration curve for a weak acid is the solution a buffer

Chemistry
1 answer:
zhuklara [117]3 years ago
5 0

Answer:

a. A buffer solution reacts with basic solutions.

c. A buffer solution reacts with acidic solutions.

e. A buffer solution resists small changes in pH

Explanation:

1. Buffer questions

a, c, and e are TRUE. A buffer resists a change in the pH when small amounts of a strong acid or base are added to it.

b is wrong. A buffer can have a pH of 7, but it can also have many other pH values.

d is wrong. Most buffers are colourless, and they resist a change in pH.

2. Titration curves

The solution is the best buffer at the mid-point of the titration curve.

In the figure below, the equivalence point is at 13 mL, so the mid-point is at 6.5 mL.  

The solution is buffered at pH 3.2.

However, the solution is a buffer at any point in the range pH = 3.2 ± 1.

That would be in the range of 1 mL to 12 mL.

The buffering ability becomes worse the further you are from the mid-point of the titration.

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KCl is an ionic salt with a formula weight of 74.54 g/mole. A 1.417 M (mole/liter) KCl solution has a density of 1064.5 grams/li
xenn [34]

Answer:

Mass of the salt:  105.6g of KCl.

Mass water: 958.9g of water.

Molality: 1.478m.

Explanation:

<em>Mass of the salt:</em>

In 1L, there are 1.417 moles. In grams:

1.417 moles KCl * (74.54g / mol) = 105.6g of KCl

<em>Mass of the water:</em>

We can determine the mass of solution (Mass of water + mass KCl) by multiplication of the voluome (1L and density 1064.5g/L), thus:

1L * (1064.5g / L) = 1064.5g - Mass solution.

Mass water = 1064.5g - 105.6g = 958.9g of water

<em>Molality:</em>

Moles KCl = 1.417 moles KCl.

kg Water = 958.9g = 0.9589kg.

Molality = 1.417mol / 0.9589kg = 1.478m

3 0
3 years ago
If a farmer wants to increase the health of his crops, he could apply a nitrogen-based fertilizer. why is nitrogen important to
Finger [1]
Not only for plants, but also for every organism and every life form nitrogen is important because  it poses as catalyst that supports different is chemical reactions of growth. N is filled with chlorophyll that actually gives you the answer on the question as chlorophyll allow plant to perform photosynthesis by absorbing energy from light that leads to the growth. So, it is important because it provides <span>photosynthesis.</span>
8 0
3 years ago
When the pH decreases from 6 to 3, the hydrogen ion, H+, increases by what?
Irina-Kira [14]

pH decreases as the hydrogen ion concentration increases.

<u>Explanation:</u>

When there is a decrease in pH, that is pH decreases from 6 to 3 then the acidity increases.

That is the pH is between 1 to 7 then it is acidic

When the pH is 7 then it is neutral

When the pH is between  7 to 14 then it is basic

As the H⁺ ion concentration increases, then the pH value decreases, here pH decreases from 6 to 3.

So the concentration of Hydrogen ion increases, pH decreases.

3 0
3 years ago
During a combustion reaction, 9.00 grams of oxygen reacted with 3.00 grams of CH4.
Monica [59]

Answer:

0.74 grams of methane

Explanation:

The balanced equation of the combustion reaction of methane with oxygen is:

  • CH₄ + 2 O₂ → CO₂ + 2 H₂O

it is clear that 1 mol of CH₄ reacts with 2 mol of O₂.

firstly, we need to calculate the number of moles of both

for CH₄:

number of moles = mass / molar mass = (3.00 g) /  (16.00 g/mol) = 0.1875 mol.

for O₂:

number of moles = mass / molar mass = (9.00 g) /  (32.00 g/mol) = 0.2812 mol.

  • it is clear that O₂ is the limiting reactant and methane will leftover.

using cross multiplication

1 mol of  CH₄ needs → 2 mol of O₂

???  mol of  CH₄  needs → 0.2812 mol of O₂

∴ the number of mol of CH₄ needed = (0.2812 * 1) / 2 = 0.1406 mol

so 0.14 mol will react and the remaining CH₄

mol of CH₄ left over = 0.1875 -0.1406 = 0.0469 mol

now we convert moles into grams

mass of CH₄ left over = no. of mol of CH₄ left over *  molar mass

                                    = 0.0469 mol * 16 g/mol = 0.7504 g

So, the right choice is 0.74 grams of methane

3 0
3 years ago
What 3 sub types of covergent plate boundaries?
Virty [35]
(1) Ocean to Continent
(2)Continent to Continent
(3)Ocean to Ocean
are the three sub types of convergent plate boundaries.
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