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Alika [10]
3 years ago
14

How do I connect a nuclear transfer pipe to an energy condenser that is connected to a tessoract?

Chemistry
2 answers:
anastassius [24]3 years ago
6 0

Answer:

Yes You use the nuclear transfuser to do that

Explanation:

Nostrana [21]3 years ago
6 0

Answer:

tessoract? also why did you stael my name?

Explanation:

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Calculate the moles of Cu in 7.4×1021 atoms of Cu.
IceJOKER [234]
1 moles -------- 6.02x10²³ atoms
 ?? moles ----- 7.4x10²¹ atoms

moles = 7.4x10²¹ / 6.02x10²³

 = 0.01229 moles

hope this helps!
5 0
4 years ago
In Charles's law, gas volume is directly related to the Celsius temperature.
kati45 [8]
Yes this is true gas is related to the celcuis temp
3 0
3 years ago
Read 2 more answers
6) (a) Calculate the absorbance of the solution if its concentration is 0.0278 M and its molar extinction coefficient is 35.9 L/
Anvisha [2.4K]

Answer:

6) (a) 0.499; (b) 31.7 %

7) 0.15

Explanation:

6) (a) Absorbance

Beer's Law is

A = \epsilon cl\\A = \text{35.9 L&\cdot$mol$^{-1}$cm$^{-1}$} $\times$ 0.0278 mol$\cdot$L$^{-1} \times $ 0.5 cm = \mathbf{0.499}

(b) Percent transmission

A = \log {\left (\dfrac{1}{T}}\right)}\\\\\%T = 100T\\\\T = \dfrac{\%T}{100}\\\\\dfrac{1}{T} = \dfrac{100 }{\%T}\\\\A = \log \left(\dfrac{100 }{\%T} \right ) = 2 - \log \%T\\\\0.499 = 2 - \log \%T\\\\\log \%T = 2 - 0.499 = 1.501\\\\\%T = 10^{1.501} = \mathbf{31.7}

7) Absorbance

A = \log \left (\dfrac{I_{0}}{I} \right ) = \log \left (\dfrac{I_{0}}{0.70I_{0}} \right ) = \log \left (\dfrac{1}{0.70} \right ) = -\log(0.70) = \mathbf{0.15}}

8 0
3 years ago
Suzanne makes a tower out of six identical plastic box. Then she uses a pan balance to measure the mass of the tower. She finds
choli [55]
Take the 72 g and divid it by 6 which would equal 12 g each
8 0
4 years ago
El ácido sulfúrico H2SO4 es uno de los compuestos que se utiliza para la producción de fertilizantes como el nitrosulfato amónic
Serjik [45]

Explanation:

12 hours ago

El ácido sulfúrico H2SO4 es uno de los compuestos que se utiliza para la producción de fertilizantes como el nitrosulfato amónico. Si disponemos de 8 mL de H2SO4 al 37 %P/P (d=1,26 g /mL), los cuales se disolvieron hasta alcanzar un volumen de solución de 400 mL, con una densidad de 1,08 g/mL. (La densidad del soluto es corresponde a 1,83 g/cm³)

5 0
3 years ago
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