Answer:
The mass of Na₂O that can be produced by the chemical reaction of 4.0 grams of sodium with excess oxygen in the reaction is 5.39 grams.
Explanation:
You know the balanced reaction:
4 NA + O₂ ⟶ 2 Na₂O
By stoichiometry of the reaction (that is, the relationship between the amount of reagents and products in a chemical reaction) react and are produced:
- Na: 4 moles
- O₂: 1 mole
- Na₂O: 2 moles
Being:
the molar mass of the compounds participating in the reaction is:
- Na: 23 g/mole
- O₂: 2*16 g/mole= 32 g/mole
- Na₂O: 2*23 g/mole +16 g/mole= 62 g/mole
Then by stoichiometry of the reaction they react and are produced:
- Na: 4 moles* 23 g/mole= 92 g
- O₂: 1 mole*32 g/mole= 32 g
- Na₂O: 2 moles* 62 g/mole= 124 g
Then you can apply the following rule of three: if 92 grams of Na produce 124 grams of Na₂O, 4 grams of Na, how much mass of Na₂O does it produce?
mass of Na₂O=5.39 g
<em><u>The mass of Na₂O that can be produced by the chemical reaction of 4.0 grams of sodium with excess oxygen in the reaction is 5.39 grams.</u></em>
Answer:
A.
Explanation:
Using the ideal gas equation, we can calculate the number of moles present. I.e
PV = nRT
Since all the parameters are equal for both gases, we can simply deduce that both has the same number of moles of gases.
The relationship between the mass of each sample and the number of moles can be seen in the relation below :
mass in grammes = molar mass in g/mol × number of moles.
Now , we have established that both have the same number of moles. For them to have the same mass, they must have the same molar masses which is not possible.
Hence option A is wrong
Answer:
8
Explanation:
When you balance the entire equation, you should get:
C5H12 + 8O2 ---> 5CO2 + 6H2O
Answer:
add 1/2 to 3/4 cup salt (sodium chloride) to the gallon ziploc bag of ice.
The pH of the diluted HCl solution is 1.3.
Explanation:
Given:
The concentrated HCl solution of 8.0 M. The 1.5 mL of 8.0 M HCl is diluted with water to 250 mL volume.
To find:
The pH of the diluted HCl solution.
Solution
- The concentration of the HCl solution before dilution =
- The volume of the HCl solution taken for dilution =
- The concentration of the HCl solution after dilution =
- The volume of the HCl solution after dilution =
Using the Dilution equation:
The concentration of diluted HCl solution = 0.048 M
In the 1 M solution of HCl, there are 1 M of hydrogen ion, then the concentration of hydrogen ions in 0.048 M of HCl will be:
![[H^+]=1\times 0.048M=0.048 M](https://tex.z-dn.net/?f=%5BH%5E%2B%5D%3D1%5Ctimes%200.048M%3D0.048%20M)
The pH of the diluted HCl solution :
![pH=-\log [H^+]\\=-\log [0.048M]=1.18 \approx 1.3](https://tex.z-dn.net/?f=pH%3D-%5Clog%20%5BH%5E%2B%5D%5C%5C%3D-%5Clog%20%5B0.048M%5D%3D1.18%20%5Capprox%201.3)
The pH of the diluted HCl solution is 1.3.
Learn more about the dilution equation here:
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