Joke lang panget nyo

Mathematics

1 answer:

Angelina_Jolie [31]3 years ago

8 0

delete your post right now please

You might be interested in

HELP ME SOLVE THIS! BRAINLY FOR WHOEVER GETS IT CORRECT!!!!!!

Pachacha [2.7K]

Answer:

the range of this function is [-7, 2) (Answer A)

Step-by-step explanation:

The "range" of this function is the list of all values that the function can take on according to the rule shown in the graph. The smallest such value (the smallest y-value) is -7, obtained when x = -2. The largest is just less than 2; we know this because there is an empty circle at (1, 2) instead of a shaded circle.

Thus, the range of this function is [-7, 2)

8 0

3 years ago

Read 2 more answers

Help help help<br> pleaseeeee<br> question down below

weeeeeb [17]

Answer:

3/5 x 100=60

3 0

3 years ago

Read 2 more answers

Mr. Brady is using a coordinate plane to design a treasure hunt for his students. The hunt begins at the flagpole. The first clu

dmitriy555 [2]

Answer:

The figure is attached and the total distance is 1031 feet.

Step-by-step explanation:

The graph is indicated in the attached figure.

For calculation of distance consider following

Point Flagpole is (0,0)

Point Clue1 is (0,5)

Point Clue2 is (6,0)

Point Clue3 is (0,-5)

So the distance is calculated as follows

$d_{T}=[d_{FP\ to\ Clue1}+d_{Clue1\ to\ Clue2}+d_{Clue2\ to\ Clue3}]*distance\ per\ unit\\d_{T}=[\sqrt{(Clue1_x-FP_x)^2+(Clue1_y-FP_y)^2}+\sqrt{(Clue2_x-Clue1_x)^2+(Clue2_y-Clue1_y)^2}+\sqrt{(Clue3_x-Clue2_x)^2+(Clue3_y-Clue2_y)^2}]**distance\ per\ unit\\$ Substituting the values

$d_{T}=[\sqrt{(0-0)^2+(5-0)^2}+\sqrt{(6-0)^2+(0-5)^2}+\sqrt{(0-6)^2+(-5-0)^2}]*50 \text{ feet}\\d_{T}=[\sqrt{(0)^2+(5)^2}+\sqrt{(6)^2+(-5)^2}+\sqrt{(-6)^2+(-5)^2}]*50 \text{ feet}\\d_{T}=[\sqrt{0+25}+\sqrt{36+25}+\sqrt{36+25}]*50 \text{ feet}\\d_{T}=[\sqrt{25}+\sqrt{61}+\sqrt{61}]*50 \text{ feet}\\d_{T}=[5+7.81+7.81]*50 \text{ feet}\\d_{T}=[20.62]*50 \text{ feet}\\d_{T}=1031 \text{ feet}\\$