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givi [52]
3 years ago
6

Help 17 points

Chemistry
1 answer:
Artemon [7]3 years ago
5 0

Answer:

1.

a. 1.2   x 10^−4 mm

b. 5.6  x 10^5  cm

c. 3.34 x 10^4  kg

d. 4.12  x 10^-4 s

2.

a. 70.5 g

b. 40.0005

c. 23500

Explanation:

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Which total mass of iron is necessary to produce 1.00 mole of copper?
Harman [31]
1 mole Fe produces 1 mole Cu 
<span> molar mass of Fe is 55.8 g / mole 
 
answer: </span><span>55.8g</span>
4 0
3 years ago
A certain liquid X has a normal boiling point of 133.60°C and a boiling point elevation constant Kb= 2.46°C kg mol^-1.Calculate
Afina-wow [57]

Answer:

136.63 °C

Explanation:

ΔTb=Tb solution - Tb pure

Where; Tb pure = 133.60°C

molar mass of solute = 121.14 g/mol

number of moles of solute; 52.2g/121.14 g/mol = 0.431 moles

molality = 0.431 moles/350 * 10^-3 = 1.23 molal

Then;

ΔTb = Kb * m * i

Kb = 2.46°C kg mol^-1

m = 1.23 molal

i = 1

ΔTb = 2.46 * 1.23 * 1

ΔTb = 3.03 °C

Hence;

Tb solution = ΔTb + Tb pure

Tb solution = 3.03 °C + 133.60°C

Tb solution = 136.63 °C

6 0
3 years ago
Why is the Atlantic Ocean growing larger, but the Pacific Ocean is growing smaller?
Anastasy [175]

Answer:

A.The Atlantic Ocean has more mid-ocean ridges than the Pacific Ocean so that keeps it growing larger.

Explanation:

Atlantic ocean is getting bigger because of the presence of spreading centers (divergent plate boundary). ... Pacific Ocean is getting smaller because the pacific plate is subducting along the subduction zones. Subduction zones are areas where old, dense plate subducts beneath a less dense plate.

7 0
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What is the temperature difference if 300 cal are used to warm water
PIT_PIT [208]

Answer:

<u>The temperature difference is</u> \frac{300}{m} Kkg^{-1}

Explanation:

The formula that is to used is :

ΔQ=msΔT

<em>where ,</em>

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  • <em>m is the mass of water taken = m (assumed)</em>
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ΔT :

\frac{300}{m*1} \\=\frac{300}{m} Kkg^{-1}

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3 years ago
Calculate the mass of 5.0x 1014 molecules of water
kvasek [131]
If the “x” stands for multiplication, that would be 5070.
7 0
3 years ago
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