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Ludmilka [50]
3 years ago
15

Calculate the energy of a photon emitted when an electron in a hydrogen atom undergoes a transition from =3 to =1.

Chemistry
1 answer:
never [62]3 years ago
6 0

Answer:

1.936\times 10^{-18}\ \text{J}

Explanation:

R_h = Rydberg constant = 2.178\times 10^{-18}\ \text{J}

n_i = Initial shell = 3

n_f = Final shell = 1

We have the relation

\Delta E=R_h(\dfrac{1}{n_f^2}-\dfrac{1}{n_i^2})\\\Rightarrow \Delta E=2.178\times 10^{-18}(\dfrac{1}{1^2}-\dfrac{1}{3^2})\\\Rightarrow \Delta E=1.936\times 10^{-18}\ \text{J}

The energy of the photon emitted here is 1.936\times 10^{-18}\ \text{J}.

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Answer:

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8 0
3 years ago
Gold has a molar (atomic) mass of 197 g/mol. consider a 2.47 g sample of pure gold vapor. (a) calculate the number of moles of g
adell [148]
N = given mass/ molar mass.
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3 0
3 years ago
CO 2 is an element. true or false
iren [92.7K]

Answer: false

Explanation:

f this helps typically an element wont have a 2 next to it, to see if something is an element or compound check for the element on the periodic table and see if the structure or name matches the one given to you on the question. for example here it is Co2 on the periodic table it's simply written as Co

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7 0
2 years ago
Read 2 more answers
What is the compound name for the formula [Ru(en)2Cl2]2+ and [Co(en)Cl2Br]-
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dlinn [17]

Answer:

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Explanation:

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4 0
3 years ago
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