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IgorC [24]
3 years ago
12

Fill in the flowing information for the element uranium

Chemistry
2 answers:
iragen [17]3 years ago
8 0
The period is 7 the group is actinides and the family is actinides
UkoKoshka [18]3 years ago
6 0

Answer:

Period: 7

Family: actinides

Group: Actinide

Explanation:

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The principle quantum number of the first d shell is
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PLEASE HELP ME I HAVE NO IDEA “Heat (thermal) energy is being applied to the substance whenever the Bunsen Burner is on. Before
svetlana [45]

TLDR: The energy was being used simply to heat the substance up.

Whenever something melts, it performs what is called a "phase transition", where the state of matter moves from one thing to something else. You can see this in your iced drink at lunch; as the ice in the cup of liquid heats up, it reaches a point where it will eventually "change phase", or melt. The same can be achieved if you heat up that water enough, like if you're cooking; when you boil eggs, the water has so much thermal energy it can "change phase" and become a gas!

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4 years ago
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3 years ago
What is the molarity of a solution that contains 224 grams of KOH in 2<br> liters of solution?
adelina 88 [10]

Answer:

\boxed {\boxed {\sf 2 \ M \ KOH}}

Explanation:

Molarity is a measure of concentration in moles per liter.

<h3>1. Grams to Moles </h3>

The first step is to convert the amount of grams given to moles. The molar mass is used. This found on the Periodic Table and it's the same value as the atomic mass, but the units are grams per mole.

We have 224 grams of KOH. Look up the molar masses for the individual elements.

  • Potassium (K): 39.098 g/mol
  • Oxygen (O): 15.999 g/mol
  • Hydrogen (H): 1.008 g/mol

Since the compound's formula has no subscripts, 1 formula unit has 1 atom of each element. We can simply add the molar masses together to find KOH's molar mass.

  • KOH: 39.098 + 15.999 + 1.008=56.105 g/mol

Use this number as a ratio.

\frac {56.105 \ g\ KOH}{1 \ mol \ KOH}

Multiply by the value we are converting: 224 g KOH

224 \ g \ KOH *\frac {56.105 \ g\ KOH}{1 \ mol \ KOH}

Flip the ratio so the units of grams KOH cancel.

224 \ g \ KOH *\frac {1 \ mol \ KOH}{56.105 \ g\ KOH}

224 *\frac {1 \ mol \ KOH}{56.105}

\frac {224}{56.105} \ mol \ KOH

3.992514036 \ mol \ KOH

<h3>2. Calculate Molarity </h3>

Remember molarity is moles per liter.

molarity = \frac{moles}{liters}

We just calculated the moles and we know there are 2 liters of solution.

molarity = \frac{ 3.992514036 \ mol \ KOH}{ 2 \ L}

molarity= 1.996257018 \ mol \ KOH/ L

<h3>3. Round and Convert Units </h3>

First, let's round. The original values have 3 and 1 significant figures. We go with the lowest number: 1. For the number we found, that is the ones place.

  • 1.<u>9</u>96257018

The 9 in the tenths place tells us to round to 1 up to a 2

2 \ mol \ KOH/ L

Next, convert units. 1 mole per liter is equal to 1 molar or M.

2 \ M \ KOH

The molarity of the solution is <u>2  M  KOH</u>

6 0
3 years ago
Read 2 more answers
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