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horsena [70]
3 years ago
15

A car traveling initially at 9.49 m/s accelerates at the rate of 0.988 m/s^2 for 3.05s. What is it’s velocity at the end of the

acceleration?
Physics
2 answers:
krok68 [10]3 years ago
7 0

Answer:

• From first equation of motion:

{  \boxed{ \bf{v = u + at}}}

substitute:

v = 9.49 + (0.988 \times 3.05) \\ v = 9.49 + 3.0134 \\ v = 12.50 \:  \: m {s}^{ - 1}

weeeeeb [17]3 years ago
6 0

Answer:

12.50 m/s

Explanation:

Vi = 9.49 m/s

a = 0.988 m/s²

t = 3.05 s

Vf = ?

Vf = Vi + at

Vf = 9.49 + (0.988)(3.05)

Vf = 12.50 m/s

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How much time would it take to go up to the moon and back
marusya05 [52]

That completely depends on your speed and the trajectory (path) you choose.

The Apollo missions took about 3 days each way.

The New Horizons spacecraft passed the moon within a couple of hours after it was launched.

4 0
3 years ago
Read 2 more answers
A resistor with r = 340 ω and an inductor are connected in series across an ac source that has voltage amplitude 490 v. The rate
Arada [10]

The value of impedance Z of the circuit, when the rate at which electrical energy is dissipated in the resistor is 316 w, is 508 ohms.

<h3>What is impedance Z of the circuit?</h3>

The impedance Z of the circuit is the ratio of voltage amplitude to the maximum current.

Z=\dfrac{V}{I}

Here, <em>V </em>is voltage amplitude and<em> I</em> maximum current.

A resistor with R = 300 Ω and an inductor are connected in series across an ac source that has voltage amplitude 490V. The rate at which electrical energy is dissipated in the resistor is 316 W.

The rate at which electrical energy is dissipated in the resistor is the product of the resistance and the square of current. Thus,

316=340\times I^2\\I=\sqrt{\dfrac{316}{340}}\\I=0.964\rm\; A

The impedance Z of the circuit is,

Z=\dfrac{V}{I}\\Z=\dfrac{490}{0.964}\\Z=508\rm\; ohm

Thus, the value of impedance Z of the circuit, when the rate at which electrical energy is dissipated in the resistor is 316 w, is 508 ohms.

Learn more about the impedance Z of the circuit here:

brainly.com/question/24225360

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5 0
2 years ago
A sound source is located somewhere along the x-axis. Experiments show that the same wave front simultaneously reaches listeners
guapka [62]

Answer:

a)   x₀ = - 2 m  , b)     y = 4.47 m

Explanation:

A wave travels in the middle with constant speed, let's use the equation of uniform motion

    v = d / t

    t = d / v

The distance to the first listeners, see attached

    d₁ = x₀-x

     t = (x₀ +7) / v

The distance to the second listener

    d₂ = x - x₀

     t = (+ 3- x₀) / v

As the wave arrives at the same time, we can equal the two equations

     (x₀ +7) / v = (3 -x₀) / v

      x₀ + 7 = 3 - x₀

      2 x₀ = 3 - 7

      x₀ = -4/2

      x₀ = - 2 m

b) The time it takes for the wave to reach the listeners of the x-axis, where the speed of sound is 340 m / s

          t = 5/340

          t = 0.0147 s

Let's look for the distance the wave travels for the listener axis and

       v = d₃ / t

       d₃ = v.t

       d₃ = 340 * 0.0147

       d₃ = 5 m

For the distance component we use the Pythagorean triangle

      d₃² = x₀² + y²

      y² = d₃² - x₀²

     y = √ (d₃² -4)

      y = √ (5² -4)

     y = 4.47 m

6 0
3 years ago
The closeness of measured values to an accepted value is the BLANK of the data ?
wlad13 [49]
When you refer to how close a measured value is to a standard, accepted or known value, you are talking about the ACCURACY of the data. This is the definition of accuracy when it comes to engineering and other fields of science. 

Accuracy is usually associated or with the term precision, as their definitions are often interchanged.
3 0
3 years ago
In a discussion person A is talking 1.2 dB louder than person B, and person C is talking 3.2 dB louder than person A. What is th
liberstina [14]

Answer: 3.84dB

Explanation:

Since person A is talking 1.2dB louder than B, we will have

A = 1.2B... (1)

Similarly, person C is talking 3.2 dB louder than person A, we have

C = 3.2A... (2)

From equation 1, B = A/1.2... (3)

To get the ratio of the sound intensity of person C to the sound intensity of person B, we will divide equation 2 by 3 to give

C/B = 3.2A/{A/1.2}

C/B = 3.2A×1.2/A

C/B = 3.2×1.2

C/B = 3.84dB

3 0
3 years ago
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