Show all your work clearly on the scratch paper) Two in-phase loudspeakers that emit sound with the same frequency are placed al
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Answer:
The new frequency (F₂ ) will be related to the old frequency by a factor of one (1)
Explanation:
Fundamental frequency = wave velocity/2L
where;
L is the length of the stretched rubber
Wave velocity =
Frequency (F₁) =
To obtain the new frequency with respect to the old frequency, we consider the conditions stated in the question.
Given:
L₂ =2L₁ = 2L
T₂ = 2T₁ = 2T
(M/L)₂ = 0.5(M/L)₁ = 0.5(M/L)
F₂ =
Therefore, the new frequency (F₂ ) will be related to the old frequency by a factor of one (1).