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Wewaii [24]
3 years ago
12

Show all your work clearly on the scratch paper) Two in-phase loudspeakers that emit sound with the same frequency are placed al

ong a wall and are separated by a distance of 5.00 m. A person is standing 12.0 m away from the wall, equidistant from the loudspeakers. When the person moves 1.00 m parallel to the wall, she experiences destructive interference for the first time. What is the frequency of the sound
Physics
1 answer:
Darya [45]3 years ago
8 0

Answer:

Explanation:

The speed of sound in air to be 343 m/s.

Given:

distance 'd' = 5 m

L = 12 m

It can be concluded that path difference must be equal to half of the wavelength when person is observing destructive interference'y' at 1 m distance from the equidistant position

Since

λ/2 = yd/L

λ/2 = (1 x 5)/12

λ = 0.833m

Frequency of the sound is given by,

f = v / λ => 343 / 0.833

f=411.6 Hz

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An astronaut is moving in space when a big explosion occurs about 50 meters behind him. How will the astronaut come to know abou
LUCKY_DIMON [66]

Answer:

The correct answer is B.

The astronaut will know due to the light from the explosion.

Explanation:

Sound and vibrations require a medium such as air to travel through. Space, there is no air. Only a vacuum. So sound and vibrations are unable to travel. Light requires no medium to travel. It can go through a vacuum.  

Therefore the Astronaut will see a bright flash of light as it travels from the explosion to outer space. It is also important to note that light can travel very far because nothing else interacts with its wave particles and as such, it cannot be impeded.

Cheers!

7 0
3 years ago
The last multiple choice answer is
N76 [4]

Answer:

Answer: C

Explanation:

The closer the city is by the ocean, the cooler it will get because of the winds it is created from the ocean. Meanwhile, Atlanta is slightly away from the ocean but wont be as cool as the Tybee Island. So the heat will hit more to the city away from the ocean.

5 0
4 years ago
In the diagram, q1=+6.25 * 10^ -8 C. What is the potential difference when you go from point A to point B? Include the correct s
Nimfa-mama [501]

Answer:

Moving a unit "positive" test charge from A to B will result in a reduction in potential

V = K Q / R      potential at a point

V2 - V1 = K Q (1 / .4 - 1 / .15) = = k Q (.15 - .4) / .06 = -4.17 K Q

V2 - V1 = -4.17 * 9 & 10E9 * 6.25 E-8

V2 - V1 = -4.17 * 562.5 J/C

V = - 2346 Volts

7 0
3 years ago
Refrigerant-134a enters an adiabatic compressor as saturated vapor at -24C and leaves at 0.8 MPa and 60C. When the mass flow r
sergey [27]

Answer:

= 287kW

Explanation:

Knowing the enthalpy data, we have to

h1=239.16kJ/kg\\h2=296.81kJ/kg

So,

E_i_n_p_u_t=mh_1

Here,

m=mass flow rate

h= Enthalpy of refrigerant at the compressor

Replacing

= 1.2 × 239.16

= 287kW

4 0
3 years ago
Can someone help me please? I’m so confused
Svetradugi [14.3K]

Answer:

what do you need help with? Like which type of print each image is?

Explanation:

5 0
3 years ago
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