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goblinko [34]
3 years ago
13

3. Tyler and his family went on a backpacking trip. They started hiking at 3:00 P.M. It took 2 hours and 30 minutes to reach the

ir campsite. After they arrived, it took 1 hour and 30 minutes to set up the campsite. What time was it when Tyler and his family finished setting up their campsite?
HURRRYYRYRY
Mathematics
1 answer:
atroni [7]3 years ago
4 0
I'm pretty sure the answer is 7:00 pm
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Which of the following represents the graph of f(x) = 3x2 - 12 ?
xxMikexx [17]
F(x) = 3x² - 12

Finding where the graph crosses the axes will help us to determine the correct graph

When x = 0,
f(0) = 3(0)² - 12
f(0) = -12

So we have one point (0, -12)

When y = 0
0 = 3x² - 12
12 = 3x²
4 = x²
√4 = x
x = ⁺/₋ 2 

So the graph crosses the x-axis at -2 and 2 and the y-axis at -12

The correct graph is option A
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3 years ago
Which expression represents the algebraic phrase “eleven less than seven times a number”?
Rzqust [24]
The answer would be 7x - 11.
8 0
3 years ago
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Use the distributive property to demonstrate that the product of 10 and -1/5 is a negative number. Make sure to include all step
emmainna [20.7K]
The answer is -2

10(-1/2)=-2
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3 years ago
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What is the value of StartFraction 1 Over 6 Superscript 0 EndFraction? One-sixth 0 1 undefined
Allisa [31]

Answer:

1

Step-by-step explanation:

just took the test :)

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I need help on question 2 i need the simplified answer and the restrictions
Anastaziya [24]

Answer:

x cannot be 5 or -3.

\frac{x+5}{x+3}

Step-by-step explanation:

The restrictions for a fraction is that the bottom cannot be 0.

So if we find when the bottom is 0 we have found the values that x cannot be.

Let's solve x^2-2x-15=0.

Since the coefficient of x^2 is 1 all we have to do is find two numbers whose product is -15 and whose sum is -2.

Those numbers are -5 and 3 since (-5)(3)=-15 and (-5)+(3)=-2.

So the factored form of the equation is:

(x-5)(x+3)=0

This means either x-5=0 or x+3=0.

We do have to solve both.

x-5=0 can be solved by adding 5 on both sides.

x-5+5=0+5

x+0=0+5

x=5

x+3=0 can be solved by subtracting 3 on both sides.

x+3-3=0-3

x+0=0-3

x=-3

So x can be any number except x=5 or x=-3.

We already factored the bottom as (x-5)(x+3).

The top is a difference of squares, x^2-a^2,

which can be factored as (x-a)(x+a).

So the top factors as (x-5)(x+5).

The fraction can then be written as:

\frac{x^2-25}{x^2-2x-15}=\frac{(x-5)(x+5)}{(x-5)(x+3)}

This can further simplified assuming x is not 5 we can write it as \frac{x+5}{x+3}.  I canceled the common factor of (x-5).

5 0
3 years ago
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