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ANEK [815]
4 years ago
5

Any compound that has at least one element from Group 17 is called a?

Chemistry
1 answer:
Dmitrij [34]4 years ago
8 0
I think it's called a Halide or a halogen
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Give the ΔH value for the decomposition of silver chloride as shown in the reaction 2AgCl(s)+127 kJ→2Ag(s)+Cl2(g).
choli [55]

Answer: \Delta H=+127kJ

Explanation:

2AgCl(s)+127kJ\rightarrow 2Ag(s)+Cl_2(g)  

Exothermic reactions are defined as the reactions in which energy of the product is lesser than the energy of the reactants. The total energy is released in the form of heat and \Delta H for the reaction comes out to be negative.

Endothermic reactions are defined as the reactions in which energy of the product is greater than the energy of the reactants. The total energy is absorbed in the form of heat and \Delta H for the reaction comes out to be positive.

As the heat is absorbed the reactants , the reaction is endothermic and \Delta H for the given endothermic reaction will be +127 KJ

6 0
4 years ago
Relationship between the variables of Pressure and Temperature of a gas?
pychu [463]

Answer:

The pressure of a given amount of gas is directly proportional to iys absolute temperature provided that that the volume does not change

7 0
3 years ago
Okay im clueless and over thinking this question can someone please help me out
Crank

A cookie made from flour, eggs, sugar, butter, and chocolate chips is an example of a heterogeneous mixture.

Also, mixing the sugar flavoring in water, since you're mixing two different states of matter.

6 0
3 years ago
Calculate the rms speed of an oxygen gas molecule, o2, at 17.0 ∘c .
ludmilkaskok [199]
The  RMS  of O2  at  17  degrees   is  calculated  as  follows

RMs= ( 3RT/m)^1/2   where

R= ideal  gas   constant  =  8.314
T=   temperature=   17+273=  290 K
M=  molar  mass   in  KG =   32/1000=  0.032  Kg

Rms  is  therefore= sqrt (3x   8.314  x290/0.032 )  =  sqrt( 226036.875

RMs=475.43

6 0
3 years ago
Read 2 more answers
For each given [H3O+] or [OH-], find the corresponding [OH-] or [H3O+] at 25°C.
-BARSIC- [3]

Answer:

a) [H3O+] = 1.00 E-10 M ⇒ [OH-] = 1.0 E-4 M

b) [H3O+] = 1.00 E-4 M ⇒ [OH-] = 1.0 E-10 M

c) [H3O+] = 9.90 E-6 M ⇒ [OH-] = 1.0 E-9 M

Explanation:

  • 14 = pH + pOH
  • pH = - Log [H3O+]

a) [H3O+] = 1.00 E-10 M

⇒ pH = - Log(1.00 E-10) = 10

⇒ pOH = 14 - 10 = 4

⇒ 4 = - Log[OH-]

⇒ [OH-] = 1.0 E-4 M

b) [H3O+] = 1.00 E-4 M

⇒ pH = 4

⇒ pOH = 10

⇒ [OH-] = 1.0 E-10 M

c) [H3O+] = 9.90 E-6 M

⇒ pH = 5

⇒ pOH = 9

⇒ [OH-] = 1.0 E-9 M

8 0
3 years ago
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