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max2010maxim [7]
3 years ago
9

What is the volume of 11.2 g of O2 at 7.78 atm and 415 K?

Chemistry
1 answer:
irina1246 [14]3 years ago
3 0

Answer:

1.53 L

Explanation:

Step 1: Given data

  • Mass of oxygen (m): 11.2 g
  • Pressure (P): 7.78 atm
  • Temperature (T): 415 K
  • Ideal gas constant (R): 0.0821 atm.L/mol.K

Step 2: Calculate the moles (n) corresponding to 11.2 g of oxygen

The molar mass of oxygen is 32.00 g/mol.

11.2 g × (1 mol/32.00 g) = 0.350 mol

Step 3: Calculate the volume of oxygen

We will use the ideal gas equation.

P × V = n × R × T

V = n × R × T / P

V = 0.350 mol × (0.0821 atm.L/mol.K) × 415 K / 7.78 atm

V = 1.53 L

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So 16 – 8 = 8; divided by 2 = 4. So, 4 is the bonding order of CO2. The molecular structure of CO2 looks like this:

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Quick question plz . .....Which one of the following is acidic oxide?
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Explanation:

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2 years ago
Question List (4 items) (Drag and drop into the appropriate area) Find the volume of HCl that will neutralize the base. Find the
expeople1 [14]

The question is incomplete, the complete question is:

The solubility of slaked lime, Ca(OH)_2, in water is 0.185 g/100 ml. You will need to calculate the volume of 2.50\times 10^{-3}M HCl needed to neutralize 14.5 mL of a saturated

<u>Answer:</u> The volume of HCl required is 290mL, the mass of Ca(OH)_2 is 0.0268g, the moles of

<u>Explanation:</u>

Given values:

Solubility of Ca(OH)_2 = 0.185 g/100 mL

Volume of Ca(OH)_2 = 14.5 mL

Using unitary method:

In 100 mL, the mass of Ca(OH)_2 present is 0.185 g

So, in 14.5mL. the mass of Ca(OH)_2 present will be =\frac{0.185}{100}\times 14.5=0.0268g

The number of moles is defined as the ratio of the mass of a substance to its molar mass.

The equation used is:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}} ......(1)

Given mass of Ca(OH)_2 = 0.0268 g

Molar mass of Ca(OH)_2 = 74 g/mol

Plugging values in equation 1:

\text{Moles of }Ca(OH)_2=\frac{0.0268g}{74g/mol}=0.000362 mol

Moles of OH^- present = (2\times 0.000362)=0.000724mol

The chemical equation for the neutralization of calcium hydroxide and HCl follows:

Ca(OH)_2+2HCl\rightarrow CaCl_2+2H_2O

By the stoichiometry of the reaction:

Moles of OH^- = Moles of H^+ = 0.000724 mol

The formula used to calculate molarity:

\text{Molarity of solution}=\frac{\text{Moles of solute}\times 1000}{\text{Volume of solution (mL)}} .....(2)

Moles of HCl = 0.000724 mol

Molarity of HCl = 2.50\times 10^{-3}

Putting values in equation 2, we get:

2.50\times 10^{-3}mol=\frac{0.000724\times 1000}{\text{Volume of solution}}\\\\\text{Volume of solution}=\frac{0.000725\times 1000}{2.50\times 10^{-3}}=290mL

Hence, the volume of HCl required is 290mL, the mass of Ca(OH)_2 is 0.0268g, the moles of

5 0
3 years ago
1. Which of the following pairs of factors affects the solubility of a particular substance? (1 point)
Lina20 [59]
<h2>Question no 1:</h2><h3>Answer:</h3>

The correct answer is option A which is temperature and the nature of solute and solvent

<h3>Explanation:</h3>
  • The solubility of a substance is its ability to dissolve in a particular solution.
  • Solubility is highly dependent on the temperature and nature of solute and solvent.
  • It is directly proportional to the temperature. As we increase the temperature, the solubility of substantial increases but for the exothermic reactions, solubility is inversely proportional to temperature.
  • Solubility is absolutely dependent on the nature of solute and solvent, as polar solute and solvents have high solubility than non polar.
<h2>Question no. 2</h2><h3>Answer:</h3>

The correct answer is option B which is a large amount of solute.

<h3>Explanation:</h3>
  • A concentrated solution contains the maximum amount of solute which can be dissolved in the solvent.
  • For example, in water sugar solution concentrated solution will contain a large amount of sugar dissolved in water without the addition of heat.
  • In dilute solution, there is a small amount of solute.
<h2>Question no. 3:</h2><h3>Answer:</h3>

The correct answer is option B which is molarity × liters of solution.

<h3>Explanation:</h3>

Molarity of a solution is the total number of moles of solute per unit volume of solution.

Its formula is:

             Molarity = Number of moles of the solute/volume of solution in liters.

    A number of moles of solute =  Molarity × Volume of the solution.

So the number of moles of solute is equal to the molarity and volume of solution. Hence correct option is B.

<h2>Question no 4.</h2><h3>Answer:</h3>

The correct answer is option D. Molarity of the dilute solution = 0.81 M

<h3>Explanation:</h3>

Given data:

        initial volume = V1 = 225 mL = 0.225 L

        Initial molarity = M1 = 0.80M

        Final volume =  V2 = 1 L

        Final molarity  = M2 = ?

Solution:

It is the dilution of the stock solution and the formula is given below:

V1M1 = V2M2

M2 = V1.M1/V2

By putting values in the formula:

M2 = 0.225 × 0.8/1

M2= 0.18

So the final molarity of the solution will be 0.18 M. Hence the correct answer is option D.

<h2>Question no. 5</h2><h3>Answer:</h3>

The correct answer is option B which is supersaturation.

<h3>Explanation:</h3>
  • Colligative properties of the solution are the properties which are not dependent on the number of particles of the solute in the solution.
  • While supersaturation of the solution means the solution containing the highest number of solute particles dissolved in the solution.
  • Since supersaturation is dependent on a number of solutes, it is not a colligative property.
<h2>Question no 6.</h2><h3>Answer:</h3>

The correct answer is option B/C, "which disrupts crystal formation of the solvent".

<h3>Explanation:</h3>
  • Depression of freezing point is the colligative property of the solution.
  • Which the lowering of the freezing point of a solution by adding the solute.
  • The addition of solute disrupts the crystal formation in the solvent, as it disrupts the intermolecular forces between solute particles.
  • Hence option B and C are the correct options because both have the same statement.
<h2>Question no 7.</h2><h3>Answer:</h3>

The correct answer is option D which is 142.

<h3>Explanation:</h3>

<u>Given data:</u>

Volume of solution = 167 ml

Percentage of solution = 85%

The volume of alcohol =?

<u>Solution:</u>

Percentage of solution ( v/v) = volume of solute/volume of solution × 100

The volume of solute = percentage × volume of solution/100

By putting values in above formula:

Volume of alcohol = 85 × 167/100 = 141.95 ml

<em><u>Hence the correct answer is option D which is approximately 142(141.95).</u></em>

8 0
2 years ago
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