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skad [1K]
2 years ago
14

MANSAH OBTAINED 150 MARKS OUT OF 240 MARKS IN AN ENGLISH TEST. WHAT WAS HER PERCENTAGE SCORE?​

Mathematics
1 answer:
Zanzabum2 years ago
3 0

Answer:

62.5%

Step-by-step explanation:

150/240 x 100

5/8 x 100

= 62.5%

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The blood platelet counts of a group of women have a bell-shaped distribution with a mean of 246.9 and a standard deviation of 6
belka [17]

Answer:

The approximate percentage of women with platelet counts within 1 standard deviation of the mean, or between 177.6 and 316.2 is 68%.

The approximate percentage of women with platelet counts between 39.0 and 454.8 is 99.7%

Step-by-step explanation:

Mean : \mu = 246.9

Standard deviation : \sigma = 0.49

Empirical rule :

1 ) 68% of the data lies within 1 standard deviation of mean  

This means 68% of data lies between: \mu-\sigmato \mu+\sigma

2) 95% of the data lies within 2 standard deviation of mean  

This means 95% of data lies between: \mu-2\sigma to\mu+2\sigma

3) 99.7% of the data lies within 3 standard deviation of mean

This means 99.7% of data lies between: \mu-3\sigma to\mu+3\sigma

Now to find the approximate percentage of women with platelet counts within 1 standard deviation of the mean, or between 177.6 and 316. 2

Use rule 1: \mu-\sigmato \mu+\sigma

246.9-69.3to 246.9+69.3

177.6to 316.2

So, according to rule 1, 68% of the data lies within 1 standard deviation of mean i.e. 68% of the data lies between 177.6 and 316.2.

Now to find  the approximate percentage of women with platelet counts between 39.0 and 454.8?

Use rule 3: \mu-3\sigma to\mu+3\sigma

\mu-3\sigma to\mu+3\sigma

39to 454.8

So, According to rule 3 : 99.7% of the data lies within 3 standard deviation of mean  i.e. 99.7% of data lies between  39.0 and 454.8

3 0
3 years ago
a rectangle has a primeter of 200 ft the length is 4 more feet than the width find the dimensions of the rectangle
zysi [14]

The length and width of the given rectangle are 52 ft and 48 ft respectively.

<h3><u>Solution:</u></h3>

The relationship between the length and breadth is given as following:

The length is 4 more feet than the width

The perimeter of the rectangle is given as 200 ft.

The formula to find the perimeter of a rectangle is:

Perimeter = 2(length + width)

Let length and width of the rectangle be denoted as ‘L’ and ‘B’

The given relationship between length and width can be written in equation form as follows:

L = 4 + B ------ eqn 1

Substitute the value of "L" in perimeter of triangle

200 = 2(4 + B + B)

200 = 2(4 + 2B)

200 = 8 + 4B

4B = 192

B = 48

Since, we know the value of width lets substitute it in eq1 to find the length.

L = 4 + 48

L = 52

Therefore, the length and width of the given rectangle are 52 ft and 48 ft respectively.

7 0
3 years ago
Grace and jack Share £140 in the ratio 3:4 work out the amout that jack gets
NISA [10]
Jack gets 46.6 repeating
7 0
3 years ago
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Two trials are conducted for an experiment. In Trial A, the measured value is 240, while the actual value is 200. In Trial B, th
Zepler [3.9K]

Answer:

A is the answer 456% and 512%

Step-by-step explanation:

Percent Errors

Trial A

Trial B

Measured Value

240

195

Actual Value

200

240

Percent Error

​?

​?

Complete the table.

Percent Errors

Trial A

Trial B

Measured Value

240

195

Actual Value

200

240

Percent Error

440440​%

435435​%

5 0
2 years ago
Help pls I dont rlly get it
svetlana [45]

Answer: The answer is 60 min.

Step-by-step explanation:

3 0
2 years ago
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