One method is to round 997 up to 1000, multiply by 8, and then subtract 8 times 3. This would give you the solution of 7976.
Another method (Which I personally wouldn't use) is to recursively double 997. This is more difficult, although effective. After you double 997, double the resulting number, and then double the resulting number from that, you have the solution. This is because 2^3 is 8.
If he hits the target 95% of the time, then you could say that he has a probability of 0.95, or 95% of hitting the target. Let p = the probability of hitting the target or p = 0.95. So you are interested that he misses the target at least once - this could be thought of as not getting a perfect score. So to get a perfect score, it is 0.95 for each target -- 0.95^15 for 15 targets is 0.464. Thus to miss at least one target he needs to NOT have a perfect score -- 1 - 0.464 = 0.536, or 53.6% of happening. Enjoy
Answer:
.7
Step-by-step explanation:
Answer:
x>3/2
Step-by-step explanation:
You would change the denominator and get the lowest common denominator. Thos would be 30. You would do 11/6 x 5/5 = 55/30. Then do 3/5 x 6/6 = 18/30. Then add 55/30 + 18/30 = 73/30 and simplify.
