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3 years ago

How does the sun cause wind?

1 answer:

6 0

Wind is caused by a difference in pressure from one area to another area on the surface of the earth. Air naturally moves from high to low pressure, and when it does, it is called wind. Generally, we can say that the cause of wind is the uneven heating of the earth's surface by the sun.

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A tank contains 0.568 mol of molecular nitrogen (N2). Determine the mass (in grams) of nitrogen that must be removed from the ta

Marizza181 [45]

Answer:

$\Delta M = 7.812 gm$

Explanation:

we know that for ideal gag we have

pV =nRT

Since volume, gas constant R and T are constant, so we have

$\frac{p}{n] = constant$

$\frac{44.7}{0.568} =\frac{22.8}{n}$

n = 0.289 mole

hence mass removed $\Delta M =( 0.568 - 0.289)*( molecular\ weight\ of \ nitrogen)$

$\Delta M = (0.568 - 0.289) *28 gm$

$\Delta M = 7.812 gm$

8 0

4 years ago

A point charge Q moves on the x-axis in the positive direction with a speed of 290 m/s. A point P is on the y-axis at y = +60 mm

aliina [53]

Answer:

Explanation:

Magnetic field due to a moving charge

B = μ₀ / 4π x (qv x r)/r²

Given

B = .3 X 10⁻⁶ T,

r = 60 x 10⁻³ m

Putting these values in the given equation

.3 x 10⁻⁶ = 10⁻⁷ x qvsinθ /( 60 x 10⁻³)²

θ = 90 °

qv = 10.8 x 10⁻³

At point P

Sinθ = 60 / 72

r² = 72 x 72 x 10⁻⁶

B = $\frac{10^{-7}\times108\times10^{-4}\times60}{72\times72\times72\times10^{-6}}$

= 0.17 μT

8 0

4 years ago

Find the distance traveled in one back-and-forth swing by the weight of a 12 in. Pendulum that swings through a 75 degree angle.

tia_tia [17]

The distance traveled by pendulum, in one back-and-forth swing is 75.75 inches.

The period of pendulum can be calculated by

$T = 2\pi \sqrt {\dfrac Lg}$

Where,

$T$ - period

$L$ - length = 12 inches

$g$ - gravitational acceleration = $\bold {9.8\rm \ m/s^2}$

Put the values,

$T = 2\pi \sqrt {\dfrac {12}{9.8}}\\\\T = 2 \times 3.14 \times \sqrt {0.122}\\\\T = 2.191$

Now, the angular displacement of the pendulum can be calculated by,

$\theta = A\times\rm \ cos(\omega T)$

Where,

$A$ - amplitude

$\theta$ - angle = $75^o$

$\omega$ - angular displacement = $2\pi/T$ = 2.866 m

Put the values and calculate for $\omega$ ,

$75 = A\times{\rm \ cos}(2.866\times 2.191)\\\\75 =A \times cos\ 6.26\\\\A =\dfrac {75}{0.99}\\\\A = 75.75 \rm \ inches$

Therefore, the distance traveled by pendulum, in one back-and-forth swing is 75.75 inches.

To know more about Amplitude of pendulum,

brainly.com/question/14840171

4 0

3 years ago

A train moves moves from rest to a speed of 25 m/s in 30.0 sec . what is its acceleration

spayn [35]

A = Delta v/Delta t
Delta v = 25 - 0 = 25
Delta t = 30
25/30 = 5/6 = 1.66 repeating

7 0

3 years ago

Read 2 more answers

1. Why should you use scientific notation when writing big numbers?

Fynjy0 [20]

Answer:

It helps the answer look clean. It also makes the work easier to work with.

Explanation:

Instead of writing a lot of zeros, all you have to do is add exponents to the number to show how much the decimal moved.

6 0

3 years ago