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3 years ago

8

The coefficient of static friction between a book and the level surface it slides on is 0.65. If the mass of the book is 0.2 kg,

what minimum initial applied force is required to slide the books across the surface?

2 answers:

just olya [345]3 years ago

7 0

Answer: 1.274 N minimum force required to slide the book across the surface

Explanation:

Mass of the book = m = 0.2 kg

Normal force acting on the book,N = mg

Coefficient of friction = $mu_s$ = 0.65

Minimum force required to slide the book across the surface= F

$F=\mu_s\times N$

$F=0.65\times 0.2 kg\times 9.8 m/s^2=1.274 N$

1.274 N minimum force required to slide the book across the surface

klemol [59]3 years ago

3 0

Answer : F = 1.274 N

Explanation :

It is given that,

Coefficient of static friction, $\mu_s=0.65$

Mass of the book, $m=0.2\ kg$

We know that the relation between static friction and the force is :

$F=\mu_s\times N$

Where N is the normal force (N = mg)

So, $F=\mu_s\times m\times g$

$F=0.65\times 0.2\ kg\times 9.8\ m/s^2$

$F=1.274\ N$

Hence, the minimum initial applied force is required to slide the books across the surface is 1.274 N.

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