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2 years ago

6

A train is moving at 15ms-1. It slows down to 10.5ms over a time of 4s. Calculate the distance it travels before stopping if acc

eleration is constant.

1 answer:

Nostrana [21]2 years ago

4 0

Answer:

3WGGRGWERGRG

Explanation:

GERAGAETGAERR GHERUERHGRRGF;SBDF;JKSRDMFNSDFLDGGD;GDVF

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What point is labeled in the scatter plot? <br><br> A. (2,8)<br> B. (7,4)<br> C. (8,2)<br> D. (4,7)

Whitepunk [10]

D. Would be your answer

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2 years ago

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Use the passage to answer the question.

Zielflug [23.3K]

The reasoning in the passage is : ( C ) The spots are the result of interference, which happens with waves but not particles

<h3>Light waves </h3>

Light passed through a slit and projected onto a screen will form a pattern which is very visible and the pattern might have dark spots if there is some form of interference. Interference is present in waves and not particles.

Hence we can conclude that the reasoning in the passage is The spots are the result of interference, which happens with waves but not particles

Learn more about light waves : brainly.com/question/25847009

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1 year ago

A 13 kg hanging sculpture is suspended by a 95-cm-long, 5.0 g steel wire. When the wind blows hard, the wire hums at its fundame

Artyom0805 [142]

Answer:

$f=81.96 \ Hz$

Explanation:

Givens

$L=95cm$

$m_{sculpture} =13kg$

$m_{wire}=5g$

The frequency is defined by

$f=\frac{v}{\lambda}$

Where $v$ is the speed of the wave in the string and $\lambda$ is its wave length.

The wave length is defined as $\lambda = 2L = 2(0.95m)=1.9m$

Now, to find the speed, we need the tension of the wire and its linear mass density

$v=\sqrt{\frac{T}{\mu} }$

Where $\mu=\frac{0.005kg}{0.95m}= 5.26 \times 10^{-3}$ and the tension is defined as $T=m_{sculpture} g=13kg(9.81 m/s^{2} )=127.53N$

Replacing this value, the speed is

$v=\sqrt{\frac{127.53N}{5.26 \times 10^{-3} } }=155.71 m/s$

Then, we replace the speed and the wave length in the first equation

$f=\frac{v}{\lambda}\\f=\frac{155.71 m/s}{1.9m}\\ f=81.96Hz$

Therefore, the frequency is $f=81.96 \ Hz$

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2 years ago

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What are the uses of a magnet?

Doss [256]

Answer:

A magnet is used in a compass to show the direction.

Magnets are used in medical equipment.

Powerful magnets are used to lift objects

they are used in refrigerator, televisions, earphones etc

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1 year ago

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A 20.0-N weight slides down a rough inclined plane which makes an angle of 30 degree with the horizontal. The weight starts from

Ulleksa [173]

Answer:

$1270.64\ \text{J}$

Explanation:

m = Mass of object = $\dfrac{mg}{g}$

mg = Weight of object = 20 N

g = Acceleration due to gravity = $9.81\ \text{m/s}^2$

v = Final velocity = 15 m/s

u = Initial velocity = 0

d = Distance moved by the object = 150 m

$\theta$ = Angle of slope = $30^{\circ}$

f = Force of friction

fd = Work done against friction

The force balance of the system is

$\dfrac{1}{2}m(v^2-u^2)=(mg\sin\theta-f)d\\\Rightarrow \dfrac{1}{2}mv^2=mg\sin\theta d-fd\\\Rightarrow fd=mg\sin\theta d-\dfrac{1}{2}mv^2\\\Rightarrow fd=20\times \sin 30^{\circ}\times 150-\dfrac{1}{2}\times \dfrac{20}{9.81}\times 15^2\\\Rightarrow fd=1270.64\ \text{J}$

The work done against friction is $1270.64\ \text{J}$ .

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2 years ago