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djyliett [7]
3 years ago
6

A train is moving at 15ms-1. It slows down to 10.5ms over a time of 4s. Calculate the distance it travels before stopping if acc

eleration is constant.​
Physics
1 answer:
Nostrana [21]3 years ago
4 0

Answer:

3WGGRGWERGRG

Explanation:

GERAGAETGAERR GHERUERHGRRGF;SBDF;JKSRDMFNSDFLDGGD;GDVF

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A 75 kg bungee jumper jumps off with zero initial speed from a high cliff with a bungee cord tied to her ankle. At some time dur
stich3 [128]

Answer:

The elastic potential energy PE=143.47kJ

Explanation:

This problem bothers on the potential energy stored in a material.

Given data

Mass of the bungee jumper

m= 75kg

Height of jump down the cliff h=195m

We know that the elastic potential energy stored is same as the potential energy of the bungee jumper

PE= 1/2kx²= mgh

Assuming g is 9.81m/s²

PE= 75*9.81*195

PE= 143471.25J

PE=143.47kJ

What is potential energy?

Potential energy is the energy possessed by a body by virtue of it position.

4 0
3 years ago
What happens to the change in the value of the speed as you increased the amount of force applied on your
nataly862011 [7]
The change of speed is proportional to the Force. If you double the Force, you double the change of speed.
3 0
3 years ago
If a second resistor with R2 = 19.0 Ω is connected in series with R1, what is the total rate at which electrical energy is dissi
luda_lava [24]

Total rate at which electrical energy is dissipated by the two resistors are V²/R  or I²R.

<u>Explanation:</u>

When the two resistors are combined in series then the total resistance gets added.

If R_{1} and R_{2} are in series then total resistance, R =

Total resistance becomes R_{1} + 19 Ω

The total electrical power dissipated is equivalent to the power dissipated.

We know,

Power = V²/R  or

Power = I²R

where, V is the potential difference between the ends

            I is the current supplied.

Therefore, total speed at which electrical power is consumed by the two resistors are V²/R  or I²R.

7 0
3 years ago
A 350-kg roller coaster car starts from rest at point A and slides down a frictionless loop-the-loop (Pig. P7.41). (a) How fast
Leona [35]

Answer:

a)Velocity of car =v=16 m/s

b)Force against the track at point B=1.15*10^{4}N

Explanation:

Given mass of roller coaster=m=350 kg

Position of A=Ha=25 m

Position of B=Hb=12 m

Net potential energy=mg(ha-hb)

Net potential energy=(350)(9.80)(25-12)

Net potential energy=44590 J

Using energy conservation

net kinetic energy=net potential energy

(1/2)mv^2=mg(ha-hb)

m=350

velocity=v=16 m/s

b)There two force acting,centripetal force upward and gravity downward.

Thus net force acting will be

Net force=(mv^2/r)-mg

Net force=14933.33-3430

Net force=1.15*10^{4} N

3 0
3 years ago
Read 2 more answers
I need help answer these questions please
jekas [21]

Answer:

1. 25 J

2. 250 J

3. 900,000 J

4. 7,500 J

Explanation:

1. The distance the wheelbarrow is tilted, d = 0.5 m

The force used to tilt the wheelbarrow, F = 50 N

The work done, W = F × d

∴ W = 50 N × 0.5 m = 25 J

2. Work done, W = Force × Distance

The applied force, F = 50 N

The distance the sand is moved, d = 5 m

∴ W = 50 N × 5 m = 250 J

3. The work done, W = The load lifted × The height to which the load is lifted

∴ W = 90,000 N × 10 m = 900,000 J

The work done, W = 900,000 J

4. The work output of the skateboard = The work input × Efficiency

Given that the skateboard is an ideal machine, we have;

The work output of the skateboard = The work input = W

W = F × d

F = 15 N, d = 500 m

∴ W = 15 N × 500 m = 7,500 J

The work output of the skateboard = W = 7,500 J.

3 0
3 years ago
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