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2 years ago

6

A train is moving at 15ms-1. It slows down to 10.5ms over a time of 4s. Calculate the distance it travels before stopping if acc

eleration is constant.

1 answer:

Nostrana [21]2 years ago

4 0

Answer:

3WGGRGWERGRG

Explanation:

GERAGAETGAERR GHERUERHGRRGF;SBDF;JKSRDMFNSDFLDGGD;GDVF

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The atoms in a solid move about freely

ivolga24 [154]

No, not exactly. They jiggle and tremble and vibrate a lot, but
they always basically stay in very nearly the same place.

It's like if you're allowed to go anywhere you want in your jail cell,
you wouldn't exactly call that "moving about freely".

6 0

3 years ago

Use the crisscross method to find the chemical formula for the ionic compound formed by strontium (Sr) and bromine (Br).

nignag [31]

Answer:it’s c SrBr2

Explanation:

8 0

3 years ago

Read 2 more answers

Refrigerant 134a enters a well-insulated nozzle at 200 lbf/in.2, 200°F, with a velocity of 120 ft/s and exits at 50 lbf/in.2 wit

riadik2000 [5.3K]

Answer:

x = 0.75801 = 75.801%

T_2 = 72..78 degree F

Explanation:

From superheated R 134 a properties table

At 200 lb/in^2 and 200 degree F

$h_1 = 138.99 Btu/lbm$

steady flow energy equation is givena s

$h_1 + \frac{v_1^2}{2} = h_2 + \frac{v_2^2}{2}$

$138.99 + \frac{120^2}{2\times 25037} = h_2 + \frac{1500^2}{2 \times 25037}$

$h_2 = 94.344 Btu/lbm$

At 90 lb/in2 Tsat = 72.78 degree F

$h_f = 35.715 Btu/lbm$

hfg = 77.345 Btu/lbm

h = hf + x hfg

$94.344 = 35.715+ x \times 77.345$

solving for x we get

x = 0.75801 = 75.801%

$T_2 = 72..78 degree F$

5 0

3 years ago

When a positively charged conductor touches a neutral conductor, the neutral conductor will:

frutty [35]

Answer:

Lose electrons

Explanation:

When a positively charged conductor touches a neutral conductor, the neutral conductor will lose electrons. Only electrons can move from one conductor to another, so if the neutral conductor ended up with a positive charge it means it lost electrons. The conductor touching and the neutral conductor both end up being charged positively.

6 0

3 years ago

55. Write the shortened notation for the ion symbol next to each element given below. A.) Calcium loses 2 negative electronsB.)

Eddi Din [679]

We are asked to write shortened notation for the ion symbol next to each element given below.

Convention:

First of all, write the shortened notation of the element.

The superscript (at the top) is the number of charges on the ion and also a + sign for a positive ion and - sign for a negative ion.

When an atom loses an electron then the charge is positive (+).

When an atom gains an electron then the charge is negative (-)

A.) Calcium loses 2 negative electrons

Since it loses 2 electrons it will have 2+ superscript.

Calcium has an atomic number of 20 (the number of protons)

$_{20}Ca^{2+}$

B.) Chlorine gains 1 negative electron

Since it gains 1 electron it will have - superscript (we don't write 1 when the charge is 1)

Chlorine has an atomic number of 17 (the number of protons)

$_{17}Cl^-$

C.) Hydrogen gains 1 negative electron

Since it gains 1 electron it will have - superscript

Hydrogen has an atomic number of 1 (the number of protons)

$_1H^-$

6 0

1 year ago