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BigorU [14]
3 years ago
10

what happens to the average molecular speed in an ideal gas if you triple the volume and keep the same temperature ?

Physics
1 answer:
kipiarov [429]3 years ago
4 0

Answer:

If you hold the temperature of an ideal gas constant, what happens to its volume when you triple the pressure? For T fixed, P is proportional to 1/V or V is proportional to 1/P. Tripling P reduces V to 1/3. ... If T is constant, the speeds of the average speeds and kinetic energy of the atomic particles remain constant.

I hope this helps!

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When you jump upwards, why don't you notice the Earth moving<br> downwards?
mixer [17]

Becuase Gravity. The Earthp pulls you down, you do not pull the earth.

6 0
3 years ago
Does someone know how to do math with that equation
mestny [16]

Answer:

f = 5 cm

Explanation:

using the thin lens equation, given as follows:

\frac{1}{f} = \frac{1}{d_{o}}+\frac{1}{d_{i}}\\

where,

f = focal length = ?

do = the distance of object from lens = 20 cm

di = the distance of image from lens = 6.6667 cm

Therefore,

\frac{1}{f} = \frac{1}{20\ cm}+\frac{1}{6.6667\ cm}\\\\\frac{1}{f} =  0.199999\ cm^{-1}\\\\f = \frac{1}{0.199999\ cm^{-1}}\\\\

<u>f = 5 cm</u>

8 0
3 years ago
In what type of job might being a difficult person not be much of a liability ?
zhannawk [14.2K]
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7 0
4 years ago
What is the magnitude of the torque about his shoulder if he holds his arm straight out to his side, parallel to the floor
const2013 [10]

Complete Question

An athlete at the gym holds a 3.0 kg steel ball in his hand. His arm is 70 cm long and has a mass of 4.0 kg. Assume, a bit unrealistically, that the athlete's arm is uniform.

What is the magnitude of the torque about his shoulder if he holds his arm straight out to his side, parallel to the floor? Include the torque due to the steel ball, as well as the torque due to the arm's weight.

Answer:

The torque is  \tau = 34.3 \  N\cdot m

Explanation:

From the question we are told that

   The mass of the steel ball is  m  =  3.0 \  kg

    The length of arm is  l =  70 \ cm  = 0.7 \  m

    The mass of the arm is m_a  = 4.0 \  kg

Given that the arm of the athlete is uniform them the distance from the shoulder to the center of gravity of the arm is mathematically represented as

       r = \frac{l}{2}

=>    r = \frac{ 0.7}{2}  

=>    r = 0.35 \ m  

Generally the magnitude of torque about the athlete shoulder is mathematically represented as

      \tau =  m_a * g * r  + m * g *  L

=>    \tau =  4 * 9.8 * 0.35 + 3 * 9.8 *  0.70

=>    \tau = 34.3 \  N\cdot m

5 0
3 years ago
6. If two objects experience the same net force, but they have different masses, which object will accelerate at
Digiron [165]

Answer:

i would say the heavier object

4 0
3 years ago
Read 2 more answers
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