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NeTakaya
3 years ago
5

1. How do galaxies change over time? 2. How are galaxies created? 3. How was Hubble important to our understanding of galaxies?

4. How does the Milky Way compare with other galaxies within the universe? 5. How do gravity and dark matter shape the galaxies and affect their environment?
Physics
1 answer:
VashaNatasha [74]3 years ago
7 0

Hi!


1. Galaxies are constantly evolving with time, and one manner that they do this is that they change their rotation. This is apparent from the knowledge we have of initially formed galaxies which are spiral like in the beginning, but over time transform into what seems like smooth, barren disks. Another difference is that some galaxies are younger than others, and the age difference is observed with younger galaxies having a higher number of stars that are also comparatively brighter, which makes these galaxies look blue. Older galaxies contain older stars, and older stars are seen to give off red light, which is why these galaxies seem red. Galaxies also undergo various physical and chemical changes, and older galaxies are more structured.


2. Galaxies are brought into formation with the major factor being gravity. The force of gravity is responsible for attracting various stars, collapsing gas, dust clouds and other dark matter into a structured body. Over time the organization becomes more defined. So basically, a galaxy starts off as clouds of dust and stars in space, which come into proximity with other similar clouds, and their subsequent interactions shape the structure of the galaxy.


3. Edwin Hubble, also known as the 'pioneer of distant stars', has contributed to out understanding of galaxies in that he was the first person to prove the existence of galaxies other than the Milky Way, through his studies on spiral nebulae (which were formerly thought to be clouds of dust and gas, but were actually galaxies). He also established the relationship of red shift of a galaxy (recession velocity) and the distance of the galaxy from the Earth - a directly proportional relationship, which is known as the Hubble's Law.


4. The Milky Way is found to be considerably larger, about ten times, than the average dwarf galaxy being 100,000 light years across in diameter. The Milky Way is home to 200 billion stars, and with the capacity (dust and gas) to give rise to billions more. The Milky Way is the biggest galaxy in the Virgo Supercluster, and is relatively old in comparison with most other galaxies within the universe.


5. Dark matter and gravity play a role in determining the structure of the galaxy and influences the environment over time. Dark matter contributes to the mass of the galaxy, and this affects the spin of the galaxy. The more the mass of a galaxy (or more massive a galaxy) the greater would be its rotation. Gravity is the acting force that holds the components of galaxy in place, such as the dust clouds, colonies of star, gas and dark matter. Gravity influences the structure in that it exerts and inward pull on the stars, resulting in the spiral arm structure of a galaxy, which over time tends to be more eclipse like.


Hope this helps!

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Two campers dock a canoe. One camper has a mass of 100.0 kg and moves forward at 3.0 m/s as he leaves the canoe to step onto the
KengaRu [80]

Answer:

V = -1.33 m/s

Explanation:

Given,

The mass of the camper, m = 100 kg

The velocity of the camper, v = 3.0 m/s

The combined mass of canoe and another camper, M = 225 kg

The velocity of the combined canoe and another camper, V = ?

According to the law of conservation of momentum,

                          MV + mv = 0  (Since the initial momentum of the dock is 0)

                             V = -mv/M

                                =  -100 x 3/225

                                = -1.33 m/s

The negative sign indicates that the combined objects moves opposite to that of the camper.

Hence, the velocity of the combined canoe and camper is, V = -1.33 m/s

6 0
4 years ago
38.4 mol of krypton is in a rigid box of volume 64 cm^3 and is initially at temperature 512.88°C. The gas then undergoes isobari
kolbaska11 [484]

Answer:

Final volumen first process V_{2} = 98,44 cm^{3}

Final Pressure second process P_{3} = 1,317 * 10^{10} Pa

Explanation:

Using the Ideal Gases Law yoy have for pressure:

P_{1} = \frac{n_{1} R T_{1} }{V_{1} }

where:

P is the pressure, in Pa

n is the nuber of moles of gas

R is the universal gas constant: 8,314 J/mol K

T is the temperature in Kelvin

V is the volumen in cubic meters

Given that the amount of material is constant in the process:

n_{1} = n_{2} = n

In an isobaric process the pressure is constant so:

P_{1} = P_{2}

\frac{n R T_{1} }{V_{1} } = \frac{n R T_{2} }{V_{2} }

\frac{T_{1} }{V_{1} } = \frac{T_{2} }{V_{2} }

V_{2} = \frac{T_{2} V_{1} }{T_{1} }

Replacing : T_{1} =786 K, T_{2} =1209 K, V_{1} = 64 cm^{3}

V_{2} = 98,44 cm^{3}

Replacing on the ideal gases formula the pressure at this piont is:

P_{2} = 3,92 * 10^{9} Pa

For Temperature the ideal gases formula is:

T = \frac{P V }{n R }

For the second process you have that T_{2} = T_{3}  So:

\frac{P_{2} V_{2} }{n R } = \frac{P_{3} V_{3} }{n R }

P_{2} V_{2}  = P_{3} V_{3}

P_{3} = \frac{P_{2} V_{2}}{V_{3}}

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7 0
3 years ago
If the period of a spring is 5 seconds what is the frequency
Scilla [17]

Answer:

C. 0.2 Hertz

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7 0
3 years ago
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7 0
3 years ago
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The speed of light is about 3.00 × 10 meters per second. What is the frequency of green light that has a wavelength about 500 na
RideAnS [48]

Answer:

The frequency of the green light is 6x10^{14}Hz

Explanation:

The visible region is part of the electromagnetic spectrum, any radiation of that electromagnetic spectrum has a speed of 3.00x10^{8}m/s in the vacuum.

Green light is part of the visible region. Therefore, the frequency can be determined by the following equation:

c = \lambda \cdot \nu  (1)

Where c is the speed of light, \lambda is the wavelength and \nu is the frequency.  

Notice that since it is electromagnetic radiation, equation 1 can be used. Remember that light propagates in the form of an electromagnetic wave (that is a magnetic field perpendicular to an electric field).

Then, \nu can be isolated from equation 1

\nu = \frac{c}{\lambda}  (2)

Notice that it is necessary to express the wavelength in units of meters.  

\lambda = 500nm . \frac{1m}{1x10^{9}nm} ⇒ 5x10^{-7}m

\nu = \frac{3.00x10^{8}m/s}{5x10^{-7}m}

\nu = 6x10^{14}s^{-1}  

\nu = 6x10^{14}Hz  

Hence, the frequency of the green light is 6x10^{14}Hz

4 0
4 years ago
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