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egoroff_w [7]
3 years ago
7

A 75 kg bungee jumper jumps off with zero initial speed from a high cliff with a bungee cord tied to her ankle. At some time dur

ing the jump, the bungee cord starts stretching. The lowest point in her jump where the bungee cord is at maximum stretch is a total drop of 195 m . What is the elastic potential energy stored in the bungee cord at the instant she reaches this lowest point?
Physics
1 answer:
stich3 [128]3 years ago
4 0

Answer:

The elastic potential energy PE=143.47kJ

Explanation:

This problem bothers on the potential energy stored in a material.

Given data

Mass of the bungee jumper

m= 75kg

Height of jump down the cliff h=195m

We know that the elastic potential energy stored is same as the potential energy of the bungee jumper

PE= 1/2kx²= mgh

Assuming g is 9.81m/s²

PE= 75*9.81*195

PE= 143471.25J

PE=143.47kJ

What is potential energy?

Potential energy is the energy possessed by a body by virtue of it position.

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3 0
4 years ago
A police car is traveling at a speed of 50 meters per second when it suddenly accelerates at a rate of 5 m/s2. How fast will the
Virty [35]

Answer:i don't know sorry good luck tho

Explanation: i have not learned it yet

6 0
4 years ago
if a moving object travels north for a distance of 105 m in 22 sec, what is it’s speed and velocity ?
artcher [175]

Answer:

Speed: 4.8 m/s

Velocity: 4.8 m/s north

Explanation:

Definitions:

- Speed is a scalar quantity, which is equal to the ratio between distance covered (d) and time taken (t):

s=\frac{d}{t}

- Velocity is a vector quantity, whose magnitude is equal to the ratio between the displacement of the object and the time taken:

v=\frac{disp.}{t}

And it also has a direction (the same as the displacement).

In this problem:

- The object travels a distance of

d = 105 m

In a time interval of

t = 22 s

So its speed is

s=\frac{105}{22}=4.8 m/s

- The displacement of the object is the same as the distance in this case, so still 105 m, covered in a time interval of 22 s; this means that the magnitude of the velocity is the same as the speed:

v=4.8 m/s

However, velocity is a vector quantity, so it also has a direction: and since the object has moved north, the direction of the velocity is north as well.

3 0
3 years ago
An object is moving east with a constant speed of 30 m/s for 5 seconds. What is the object’s acceleration?
Shtirlitz [24]

Answer:

6 m/s²

Explanation:

From the question given above, the following data were obtained:

Velocity (v) = 30 m/s

Time (t) = 5 s

Acceleration (a) =..?

Acceleration is defined mathematically as:

Acceleration (a) = Velocity (v) /time (t)

a = v /t

With the above formula, we can obtain the acceleration of the object as follow:

Velocity (v) = 30 m/s

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Acceleration (a) =..?

a= v/t

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7 0
4 years ago
Suppose that the electric potential outside a living cell is higher than that inside the cell by 0.0677 V. How much work is done
Lina20 [59]

Answer: Recall that

Work (W) = - e × ∆V

Where

Charge of electron= 1.6 × 10^ -19 c

And from the question we were given change in potential as = -0.0677V

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Work= 1.0832 × 10^-20J

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6 0
3 years ago
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