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Vikki [24]
3 years ago
14

How to find resultant force?

Physics
1 answer:
LuckyWell [14K]3 years ago
4 0

Explanation:

To find the resultant force subtract the magnitude of the smaller force from the magnitude of the larger force. The direction of the resultant force is in the same direction as the larger force

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A clay ball (mass = 0.25kg) has a rightward momentum of +1.75 kg∙m/s. A second clay ball (mass = 0.25 kg) has a leftward momentu
julia-pushkina [17]

1)

\begin{gathered} E1=\frac{1}{2}m_1v_1^2+\frac{1}{2}m_1v_2^2 \\ where: \\ m_1=m_2=0.25kg \\ v_1=7m/s \\ v_2=-7m/s \\ so: \\ E1=\frac{1}{2}0.25(7^2)+\frac{1}{2}0.25(7^2) \\ E1=6.125+6.125 \\ E1=12.25J \end{gathered}

Answer:

d. 12.25J

------------------------

2)

According to the conservation of energy:

\begin{gathered} E1=E2 \\ so: \\ E2=12.25J \end{gathered}

Answer:

b. 12.25

-------------------------------

3)

P1=m_1v_2+m_2v_2=+1.75-1.75=0

Answer:

d. 0 kg∙m/s

-----------------------------------------

4)

Using conservation of momentum:

\begin{gathered} P1=P2 \\ so: \\ P2=0 \end{gathered}

Answer:

b. 0 kg•m/s

3 0
1 year ago
Current is constant at all points in a parallel circuit.<br><br> True<br> False
Sergio [31]
This is false. Current is the speed of the charge, 1 amp of current is 1 coulomb per second. So you can imagine the current of a circuit as the current of a river. In a parallel circuit, the river breaks into two separate streams. Some of the water goes down one river, some goes down the other. However, the total amount of water/coulombs never changes. This means that some of the total current will go down one river, and one the other. However, with less coulombs now the current will decrease. 

Long story short, since there are two paths, the charge will split and depending on the resistance of each parallel stream a different amount of charge will go down each branch.  
5 0
3 years ago
#4<br> HELP PLEASE!<br> Find Gravitational Potential Energy! <br> THANK YOU!
Scilla [17]

Answer:

\Delta GPE=-3.92\ 10^9\ J

Explanation:

<u>Gravitational Potential Energy</u>

It's the capacity of an object to do work due to its relative height from a fixed reference point.

It's computed as

GPE=m.g.h

Where m is the mass of the object, h is its height and g is the acceleration of gravity, g=9.8 m/sec^2

The mass of water is given as

m=8,000,000\ kg

The height above the rocks is h=50 m. Let's compute the GPE

GPE_1=(8,000,000\ kg)(9.8\ m/s^2)(50\ m)

GPE_1=3,920,000,000\ Joule

It should be expressed in scientific notation

GPE_1=3.92\ 10^9\ J

The GPE at the bottom, where h=0

GPE_2=0

The change of gravitational potential energy is:

\Delta GPE=GPE_2-GPE_1

\boxed{\Delta GPE=-3.92\ 10^9\ J}

8 0
3 years ago
When wind turns the blades of a wind turbine and then this energy is used to power homes, this is an example of an energy transf
My name is Ann [436]

When wind turns the blades of a wind turbine and then this energy is used to power homes, this is an example of an energy transfer from mechanical to electrical energy.

<h3>What is Wind power?</h3>
  • In order to produce electricity, wind turbines are mostly used in wind power or wind energy.
  • In comparison to burning fossil fuels, wind energy is a well-liked, environmentally friendly, renewable energy source.
  • Wind energy, like all other forms of energy production, has the potential to have negative effects on the environment, including the loss, fragmentation, or degradation of habitat for animals, fish, and plants.
  • Additionally, flying animals like birds and bats could be harmed by turbine blades that are in motion.
  • Wind energy is economical.
  • After the production tax credit, land-based utility-scale wind is one of the least expensive energy sources on the market at 1-2 cents per kilowatt-hour.

Learn more about wind power here:

brainly.com/question/13266865

#SPJ4

8 0
1 year ago
The box is pushed to the right with a force of 40 Newtons and it just begins to move what is the maximum static frictional force
Vesnalui [34]

Answer:

The maximum static frictional force is 40N.

Explanation:

When an object of mass M is on a surface with a coefficient of static friction μ, there is a minimum force that you need to apply to the object in order to "break" the coefficient of static friction and be able to move the object (Called the threshold of motion, once the object is moving we have a coefficient of kinetic friction, which is smaller than the one for static friction).

This coefficient defines the maximum static friction force that we can have.

So if we apply a small force and we start to increase it, the static frictional force will be equal to our force until it reaches its maximum, and then we can move the object and now we will have frictional force.

In this case, we know that we apply a force of 40N and the object just starts to move.

Then we can assume that we are just at the point of transition between static frictional force and kinetic frictional force (the threshold of motion), thus, 40 N is the maximum of the static frictional force.

3 0
3 years ago
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