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AlladinOne [14]
3 years ago
10

___________is the rate at which electric charges move through a conductor. *

Physics
1 answer:
Over [174]3 years ago
6 0
The answer is voltage. :)
this is because voltage is the rate that electric charges move through a conductor.
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Study the example and choose the influence on perception. Those computer geeks are all the same. They spend all day playing vide
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They spend all day playing video games and programming their computers to serve them breakfast. I don't think I've ever seen one reading a real book or throwing a baseball. Why, they're almost like machines!  
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Is an example of stereotyping. Stereotyping happens when a person applies a single group behavior or minority behavior to a whole group ‘s behavior sharing the same characteristic.</span>
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3 years ago
I’m so confused. please help. i don’t know what i’m suppose to do
aniked [119]

Answer:

Maybe put them in order ????

Explanation:

4 0
3 years ago
An object of mass 'm' is on an inclined plane with an
Levart [38]

Answer:

F_{\text{par}} = F_{\text{frict}}

F_{\text{norm}} = F_{\text{perp}}

Explanation:

See attachment for complete work.

Download pdf
7 0
2 years ago
A 1.1-kg uniform bar of metal is 0.40 m long and has a diameter of 2.0 cm. When someone bangs one end of this bar, a 1.5 MHz sho
lyudmila [28]

Answer:

\lambda = 2.22\times 10^{-3}\ m

Explanation:

Given,

mass of the bar = 1.1 Kg

length of rod, l = 0.40 m

diameter of the rod, d = 2 cm

frequency, f = 1.5 MHz

time, t = 0.12 ms

wavelength of the shock wave = ?

Speed of the wave =\dfrac{L}{t}=\dfrac{0.40}{0.12\times 10^{-3}}

   v = 3333.33 m/s

wavelength of the wave

\lambda = \dfrac{v}{f}= \dfrac{3333.33}{1.5\times 10^6}

\lambda = 2.22\times 10^{-3}\ m

6 0
3 years ago
A. How many calories are needed to raise the temperature of 1 gram of water by 1 °C?
sweet-ann [11.9K]

A) 1 cal

B) 80 cal

C) 540 cal

Explanation:

A)

The amount of heat energy needed to raise the temperature of a certain mass of a substance is given by

Q=mC\Delta T

where

m is the mass of the substance

C is the specific heat capacity

\Delta T is the change in temperature

In this problem:

m = 1 g is the mass of water

C=1 cal/g^{\circ}C is  the specific heat capacity of water

\Delta T=1^{\circ}C is the change in temperature

So, the heat needed is

Q=(1)(1)(1)=1 cal

B)

For a solid substance at its melting point, the amount of heat needed to melt completely the substance is given by

Q=m\lambda_f

where

m is the mass of the substance

\lambda_f is the specific latent heat of fusion of the substance

In this problem:

- The ice is already at melting point, 0 °C

- Mass of the ice: m=1g

- Specific latent heat of fusion of ice: \lambda_f=80 cal/g

So, the heat needed is

Q=(1)(80)=80 cal

C)

For a liquid substance at its boiling point, the amount of heat needed to boil completely the substance is given by

Q=m\lambda_v

where

m is the mass of the substance

\lambda_v is the specific latent heat of vaporization of the substance

In this problem:

- The water is already at boiling point, 100 °C

- Mass of the water: m=1g

- Specific latent heat of vaporization of water: \lambda_v=540 cal/g

So, the heat needed is

Q=(1)(540)=540 cal

5 0
3 years ago
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