Find value of the expressions a =4, b=2 and c =3 then 2(a+3b)-(b+c)

Substitute this equation x+3y=18 & -x-4y=-25

sveticcg [70]

Answer:

{x,y} = {3/7,-43/7}

Step-by-step explanation:

System of Linear Equations entered :

[1] x + 3y = -18

[2] -x + 4y = -25

Graphic Representation of the Equations :

3y + x = -18 4y - x = -25

Solve by Substitution :

// Solve equation [1] for the variable x

[1] x = -3y - 18

// Plug this in for variable x in equation [2]

[2] -(-3y-18) + 4y = -25

[2] 7y = -43

// Solve equation [2] for the variable y

[2] 7y = - 43

[2] y = - 43/7

// By now we know this much :

x = -3y-18

y = -43/7

// Use the y value to solve for x

x = -3(-43/7)-18 = 3/7

Solution :

{x,y} = {3/7,-43/7}

5 0

3 years ago

How many solutions does the following system of equations have? 2y= 5x + 4 1 = 3x + 2

Elden [556K]

Looks like a pretty regular system, no parallel lines. In fact the second equation is a vertical line as written; not sure if that's a typo. Either way,

Answer: EXACTLY ONE SOLUTION

4 0

3 years ago

Please can I have an explanation also, I am terrible at these kinds of questions!

wlad13 [49]

Answer:

The fraction of the beads that are red is

Step-by-step explanation:

Algebraic Expressions

A bag contains red (r), yellow (y), and blue (b) beads. We are given the following ratios:

r:y = 2:3

y:b = 5:4

We are required to find r:s, where s is the total of beads in the bag, or

s = r + y + b

Thus, we need to calculate:

$\displaystyle \frac{r}{r+y+b} \qquad\qquad [1]$

Knowing that:

$\displaystyle \frac{r}{y}=\frac{2}{3} \qquad\qquad [2]$

$\displaystyle \frac{y}{b}=\frac{5}{4}$

Multiplying the equations above:

$\displaystyle \frac{r}{y}\frac{y}{b}=\frac{2}{3}\frac{5}{4}$

Simplifying:

$\displaystyle \frac{r}{b}=\frac{5}{6} \qquad\qquad [3]$

Dividing [1] by r:

$\displaystyle \frac{r}{r+y+b}=\displaystyle \frac{1}{1+y/r+b/r}$

Substituting from [2] and [3]:

$\displaystyle \frac{r}{r+y+b}=\displaystyle \frac{1}{1+3/2+6/5}$

Operating:

$\displaystyle \frac{r}{r+y+b}=\displaystyle \frac{1}{\frac{10+3*5+6*2}{10}}$

$\displaystyle \frac{r}{r+y+b}=\displaystyle \frac{10}{10+15+12}$

$\displaystyle \frac{r}{r+y+b}=\displaystyle \frac{10}{37}$

The fraction of the beads that are red is $\mathbf{\frac{10}{37}}$

8 0

3 years ago

PLEASE HELP IM BEING TIMED!!! WILL MARK BRAINLIEST FOR CORRECT ANSWER!!! 100PTS!!!

amid [387]

Answer:

B and D.

Step-by-step explanation:

We know that when we added the two functions together, we get:

$h(x)=-x+9$

However, when we multiplied them together, we get:

$j(x)=-9x$

Let's first consider what we can determine from this.

If we add them together, we get a linear equation. However, this doesn't mean that our two original functions are linear since if we have, say, -x^2 and x^2-x+9, they will cancel and form a linear equation if we add them together.

However, since we know that if we multiply the two functions together, we get a linear equation, this means that both our original functions must be linear.

But, if we multiplied two linear functions, then we should get a quadratic, since x times x will yield x².

Therefore, this means that one of our linear functions is a horizontal line with no x variable. This is the only way to have a linear equation when multiplied.

Therefore, we have determined that both of our original functions are linear functions, and one (only one of them) is a horizontal line.

Let's go through each of the answer choices.

A) Both functions must be quadratic.

This is false as we determined earlier. If this was true, then the resulting function should be a quartic and not a line. A is false.

B) Both functions must have a constant rate of change.

Remember that all linear equations have a constant rate of change.

Since we determined that both our original functions are linear equation, this means that both our functions will have a constant rate of change.

So, B is true.

C) Both functions must have a y-intercept of 0.

Remember that one of our functions is a horizontal line.

If the y-intercept was 0, then the equation of our horizontal line will be:

$y=0$

And we know that anything multiplied by 0 will give us 0. However, the product of our function is -9x.

So, C cannot be true.

Rather, only our linear equation (not the horizontal line) may have a y-intercept of 0.

D) The rate of change of either f(x) or g(x) must be 0.

Remember that we determined that one of our lines must a horizontal.

Remember that horizontal lines have a slope of 0. In other words, the rate of change is 0.

So, D is true.

E) The y-intercepts of f(x) and g(x) must be opposites.

Well, since B and D is are true, this must be false since we can only select two options ;D

But, we can think about this. Note that if we multiply the two functions, we have a function without a y-intercept.

Remember that our horizontal line is not 0. So, the y-intercept of the horizontal line is a number.

So, the opposite of a number is another number.

So, if we multiply two non-zero numbers, we must get another number.

However, from our product, j(x)=-9x, we don't have another number. The y-intercept from this is 0.

Therefore, the two y-intercepts cannot be opposites of each other. If it was so, then we should have a y-intercept. So, E must be false.

In fact, this means that the y-intercept of our line (not the horizontal one) must be 0.

So, our answers are B and D.

And we're done!

Edit: Some (minor) errors in reasoning. Sorry!

4 0

3 years ago

Read 2 more answers

Need help in algebra fast Please help

Bogdan [553]

Answer:

A

Step-by-step explanation:

because it's not equal to it is dashes ----

8 0

3 years ago

Find value of the expressions a =4, b=2 and c =3 then 2(a+3b)-(b+c)​

Find value of the expressions a =4, b=2 and c =3 then 2(a+3b)-(b+c)