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Alexxandr [17]
3 years ago
13

Please help. Real answers please.

Mathematics
2 answers:
Savatey [412]3 years ago
5 0

Answer:

23 square ft

Step-by-step explanation:

Vaselesa [24]3 years ago
3 0

Answer:

23 SQUARE feet i think

Step-by-step explanation:

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Can someone please help me?
Nesterboy [21]

Answer:

2

Step-by-step explanation:

i dont know

8 0
2 years ago
Please can you help me I'll mark brainiest please and it's being timed!!
Scrat [10]

Answer:

Step-by-step explanation:

The point ( -2 , 3) lies in the 2nd quadrant

Point are generally in the form (x , y). The point you need to plot is ( -2 , 3) which means the value of x = -2 and the value of y = 3.

I have attached an image you can check it out.

8 0
2 years ago
Plzz hurry<br> 12/19(x-22)=38-6x-3
nadya68 [22]

Answer:

x = 929/126

Step-by-step explanation:

12/19(x-22)=38-6x-3

Combine like terms

12/19(x-22)=35-6x

Multiply each side by 19

19* 12/19(x-22)=19*(35-6x)

12( x-22) = 19*(35-6x)

Distribute

12x - 264 = 665 - 114x

Add 114x to each side

12x +114x - 264 = 665 - 114x+114x

126x -264 = 665

Add 264 to each side

126x-264+264 = 665+264

126x = 929

Divide each side by 126

126x/126 = 929/126

x = 929/126

4 0
3 years ago
Read 2 more answers
The function f(x) = 2x + 510 represents the number of calories burned when exercising, where x is the number of hours spent exer
riadik2000 [5.3K]

Answer: 789 calories burned while combining diet with 2 hours of exercise

Step-by-step explanation:

we have that

f(x)=2x+510

g(x)=200x-125

we know that

(f+g)(x)=f(x)+g(x)

substitute

(f+g)(x)=2x+510+200x-125

(f+g)(x)=202x+385

Find (f+g)(2)

For x=2 hours

substitute

(f+g)(2)=202(2)+385

(f+g)(2)=789\ calories

therefore

The answer is

789 calories burned while combining diet with 2 hours of exercise

8 0
3 years ago
GIVING BRAINLIEST WHOEVER ANSWER THIS CORRECT THANK U.
Sonja [21]

Answer:

The coordinates of Y' and Z' are, respectively Y'(6,-1) Z'(-2,0)

Step-by-step explanation:

Translations

A given point A(x,y) when translated by the rule (h,k) maps to A'(x+h,y+k).

We are given the point X(3,-2) and its image at X'(2,-4). The rule for the translation used is:

(h,k)=(2,-4)-(3,-2)=(2-3,-4+2)=(-1,-2)

If we apply the same translation to the point Y(7,1) we get the image Y'(7-1,1-2)=Y'(6,-1).

If we apply the same translation to the point Z(-1,2) we get the image Z'(-1-1,2-2)=Z'(-2,0).

The coordinates of Y' and Z' are, respectively Y'(6,-1) Z'(-2,0)

it's a example from another eqaqthion

6 0
2 years ago
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